Consider a cell based on the following reaction: GeO(s) + H2O(l) + 2 Ag+(aq) → GeO2(s) + 2 H+(aq) + 2 Ag(s) If [Ag+] = 1 M, at 25°C
pH = (E - E°)/0.0592 V.
pH = 2(E - E°)/0.0592 V.
pH = 2(E° - E)/0.0592 V.
pH = (E° - E)/0.0592 V.
This question is solved by nernst equation.
PH= - log [H+ ]
Consider a cell based on the following reaction: GeO(s) + H2O(l) + 2 Ag+(aq) → GeO2(s)...
For the following reaction: NiO2(s) + 4 H+(aq) + 2 Ag(s) → Ni2+(aq) + 2 H2O(l) + 2 Ag+(aq) ℰ° = 2.48 V Calculate the pH of the solution if ℰ = 2.39 V and [Ag+] = [Ni2+] = 0.029 M. (See this table.)
For the following reaction: NiO2(s) + 4 H+(aq) + 2 Ag(s) → Ni2+(aq) + 2 H2O(l) + 2 Ag+(aq) ℰ° = 2.48 V Calculate the pH of the solution if ℰ = 2.09 V and [Ag+] = [Ni2+] = 0.045 M. (See this table.)
Consider the following reaction. Mg(s)+2Vo; (aq)+ 4 H* (aq)Mg2+(ag)+ 2 VO2 (aq)+ H2O(l) Ecell 3.37 V. Part A Calculate the AGo for the reaction. Express your answer to three significant figures. Consider the following reaction. Mg(s)+2Vo; (aq)+ 4 H* (aq)Mg2+(ag)+ 2 VO2 (aq)+ H2O(l) Ecell 3.37 V. Part A Calculate the AGo for the reaction. Express your answer to three significant figures.
A galvanic cell based on the following reactions Cu 2+ (aq) + 2e- + Cu(s) E°=0.339 V (AD + 14H(aq) + 6e-4 2Cr 3+(aq) + 7 H2O(1) Eo=1.330 V a) Write the overall cell reaction and determine its voltage. b) If the E value of the galvanic cell is 1.2 le of the galvanic cell is 1.254 V, calculate the pH of the cell when [Cu2+]=0.00010 M, Cr-0,2-1=0.00460 M, Cr3+1=1.0x102 M. The Nerst equation is E=E - (0.0592/n)logQ
Consider the following electrochemical cell. Ag(s) | Ag+(aq) || Cr3+(aq) | Cr(s) Determine the overall reaction and its standard cell potential (in V) at 25°C for this reaction. (Include states-of-matter under the given conditions in your answer. Use the lowest possible whole number coefficients.) Overall reaction (please provide)= standard cell potential V= Is the reaction spontaneous at standard conditions?
Consider a voltaic cell based on the half-cells: Ag+ (aq) + e - Ag(s) E* = +0.80 V Pb2+(aq) + 2 e-Pb(s) E* = -0.13 V Identify the anode and give the cell voltage under standard conditions: = 0.67 V Ag: E cell B. Pb: E cell = 0.67 V OC. Pb: E cell = 0.93 V D. Pb: E cell = -0.67 V E. Ag: E cell = 0.93 V
QUESTION 13 Consider a voltaic cell based on the half-cells: Ag (aq) + e - Ag(s) E = +0.80 V Sn2+ (aq) + 2 e Sn(s) E = -0.14 V Identify the anode and give the cell voltage under standard conditions: O A Sn: Eºcell = -0.66 V B. Sn; Eºcell = 0.66 V O C. Ag: Eºcell = 0.67 V D. Ag: Eºcell = 0.94 V E. Sn; Eºcell = 0.94 V
cell A voltaic cell employs the following redox reaction: Cu(s) + 2 Ag+ (aq) – Cu 2+ (aq) + 2 Ag(s) The E° for the reaction is +0.46 V. The initial (nonstandard) conditions are: [Ag +] = 0.025M; [Cu 2+] = 2.0 M Part a. Write the half-reaction that occurs at the anode. Part b. Write the half-reaction that occurs at the cathode. Part c. How many electrons are transferred in this reaction? Part d. What is the cell potential,...
Calculate the cell potential for the following reaction: Mg (s) + Ag₂SO₄ (aq) → 2 Ag (s) + MgSO₄ (aq) E° (Mg²⁺/Mg) = -2.37 V E° (Ag⁺/Ag) = 0.80 V
Find Ecell for an electrochemical cell based on the following reaction with [MnO4−]=1.50M, [H+]=1.50M, and [Ag+]=0.0140M. E∘cell for the reaction is +0.88V. MnO4−(aq)+4H+(aq)+3Ag(s)→MnO2(s)+2H2O(l)+3Ag+(aq) Find for an electrochemical cell based on the following reaction with , , and . for the reaction is . 0.75 V 1.01 V 0.84 V 0.92 V