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If 80.00 g of water at 22.3°C is heated so that the water reaches a temperature...

If 80.00 g of water at 22.3°C is heated so that the water reaches a temperature of 33.2°C then how much heat did the water gain? (Q > 0) Use 0.99823 cal/g°C as the specific heat of water. Report your answer to two (2) decimal places.

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Answer #1

uring equation, Q = mSot = 80.0 x 0.99823 x ( 33.2 - 22:3) Q = 870.456 Cal.

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