PLEASE UPVOTE THE SOLUTION
this is similar to PQ'+PQ
Take A as common we get an expression P(Q+Q')
According to boolean algebra rule Q+Q'=1 hence our expression reduces to P.
In our expression P=(A+B+C), Q=(D+E)
(A+B+C)(D+E)'+(A+B+C)(D+E)
=(A+B+C)((D+E)')+(D+E))
=(A+B+C)(1)
=A+B+C
OPTION A
PLEASE UPVOTE THE SOLUTION
1. Simplify the Boolean expression (A+B+C)(D+E)' + (A+B+C)(D+E) and choose the best answer. 1. A+B+C 2....
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