Question

WE. MASTER IT HINTS: GETTING STARTEDI IMSTUCK A person with weight 900 N stands d 3.00 m away from the wall on a 7.00 m beam, as shown irn this figure. The weight of the beam is 5,000 N. Define upward as the positive y direction and to the right as the positive x direction. 300 (a) Find the tension in the wire. (Enter the magnitude only.) (b) Find the horizontal component of the hinge force. (Indicate the direction with the sign of your answer.) (c) Find the vertical component. (Indicate the direction with the sign of your answer.) IN Noed Helo? Read It

Answer 1

Given data: weight = 900 N d = 3m l = 7m weight of the beam = 5,000 a) Not barque about part 'o' is zero 3 times + 5,000 times 3.5 = T sin 30 times l 900 times 3 + 5,000 times 3.5 = T times 0.5 times 7 2700 + 17500 = T(3.5) 20200 = T(3.5) T = 20200/3.5 T = 5771.42 N \r\n b) The horizontal component of the hinge H_2 = T cos 30 = T squareroot 3/2 = squareroot 3/2 times 5771.42 = 0.866025 times 5771.42 = 4998.196 N(left) H_2 = -4998.196 N c) Vertical component H_1 + T sin 30 = 900 + 5,000 H_1 + (5771.42 times 0.5) = 5900 H_1 + 2885.71 = 5900 H_1 = 5900 - 2885.71 H_1 = 3014.29 H_1 = -3014.29 N vertical component of is downwards