Question

TUTTI 1. Find the distance betweenthe two planes. x – 2y + 3z = -4 and x – 2y + 3z = 2.

Answer 1

. Given plancs - x-2y+32=-4 - 0 x-2y+32=2 If Ax+By+C2+120 and Axtøy +CZ +D250 is a plane equation, then distance between planes can be found using the following formula i. de P2-B, ) SA²+B+C² Hare the two plancs which are given are parauet. so that the planes 0 2 ② are paralice, in Aal, B= -2, (=3, D = 44, D2 = -2 distance between a = [D2 - DIL two plones VA²+B²+(² = 1-2-41 1²+(-23 + ² 1-61 Sit 4+9 (52 3 575 d = 3 1 2 2

* The they given plancs satisfied are the paralele plones since condition, that is are Two plones; Axt a x+azy + Az Z=0 b,x+ b2y+b32=d parand:- If the ratio equality is true checkingQ=1 42 = -2,, 23=3 C==4 b1 b2 = -2, 63=3 , d=2 in the given plones are paralice

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