Question

def calculate_total(price_list: List[list]) -> int:
"""Return the sum of all second elements in the sublists of price_list.

Precondition: price_list is a list of lists of length 2, and the second
element of it sublist is an int.

>>> price_list = [["apple", 1], ["sugar", 5], ["mango", 3],
... ["coffee", 9], ["trail mix", 6]]
>>> calculate_total(price_list)

Answer 1

In this Python program

- We have defined a function called calculate_total which accepts a list and returns an int variable.

- In the list price_list, we have a list of lists which needs to satisfy 2 conditions one of them is it should have length 2 and also the 2nd element in the sublist should be an int

- Only those sublists which satisfy the above 2 conditions, those 2nd elements in the sublist got summed up

- Finally we are returning the int variable called sum as an output

Program:

def calculate_total(price_list: list) -> int:
sum=0
for i in price_list:
if( len(i)==2 and isinstance(i[1], int) ):
sum=sum+i[1]
return sum

price_list = [["apple", 1], ["sugar", 5], ["mango", 3], ["coffee", 9], ["trail mix", 6]]
print(calculate_total(price_list))

main.py 1 def calculate_total(price_list: list) -> int: sum=0 for i in price_list: if( len(i)==2 and isinstance(i[1], int)): sum=sum+i[1] return sum vouw 8 price_list = [["apple", 1], ["sugar", 5], ["mango", 3], ["coffee", 9], ["trail mix", 6]] 9 print(calculate_total(price_list)

Output:

24 ... Program finished with exit code o Press ENTER to exit console.

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