Question

for this matlab code what is the value of ires at the end of the code?

ires = 0; for index = 10:-2:4 if index == 6 break; end ires = ires + index; end

Answer 1

ANSWER : HERE IS THE ANSWER FOR YOUR QUESTION:

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             CODE:

ires=0;
for index =10:-2:4
if index==6
break;
end
ires=ires+index;
end
ires

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SNIPPET:

HNMOCO ires=0; for index -10:-2:4 if index==6 break; end ires=ires+index; end ires

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OUTPUT:

ires = 18

EXPLANATION:

here we are using for loop from 10 to 4 with stride of 2 . that means index value would be 10 and then 8 and so on..upto 4

in 1st iteration , ires would be 10

in second iteration  , ires would be 10 + 8 = 18

in third iteartion , the value of index would be 6 and it will break the for loop.

thus ires would contain the value as 18

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