Question

The height of the helicopter from the ground is given by h = 3.00 t^3. Here, the unit of h is m and the unit of t is s. After t = 2.00s, a small postal carriage is dropped from the helicopter. How long does it take for the postal mail to fall and reach the ground?
solution is 7.96s why?

Answer 1

Height ha 3+3 at t= 25cc, ha 3x a3 = 94 m - Ground Velocity of helicopter VCH) a dvema (3+3) VC+) = 3 x 3+2 = 9t2 vet) = us axe? = 36 mis upwards. Taking upward direchon to be positiuc: us+ 36 mis ( Inihal velocily of poslal mail) $ = -5 5 - 24 m a = -9.8 mis2 At t2 sec. at2 $ ut + * -94 36t + (-9-8)42 4.9+? - 36t 36 1 736)? 44.9) 6-24 2x4.9 we get ta 397.96 sce orta -0.69 sec Not possible t=7.96 Suc CS Scanned with CamScanner