Question

For 0.030 MM H2CO3H2CO3, a weak diprotic acid, calculate the following values. Use ionization constants of H2CO3H2CO3: K1=4.4×10−7,K2=4.7×10−11 K1=4.4×10−7, K2=4.7×10−11, as necessary.

A) [H3O+][H3O+] Express your answer using two significant figures.

B) [HCO−3][HCO3−] Express your answer using two significant figures.

C) [CO2−3][CO32−] Express your answer using two significant figures.

pH of diprotic weak acid is not given?

Answer 1

Но (оз +И,0 H103 + H₂o 2 Изо+ Иto, .. H₂o++ (03 k2 = 4.7x10-11 - Ч.ЧҮlo Here, we can see that Ka LLK, H₂ 103 is very weak auid: as, its first dissociation constant ki is very less so it is onsidered as weak audos for weak and, if k is extremely small (of the order 10-om Der less), we can use 640aviy ox posjoy { al lak + Cu, o+) CHzo *) - Е. С него. Hot 2 ч. Чу 10-7 xo.ozo CHzot] = І.Чахо-Чrt. Сно* - ). | X(о-м . . 1 ki is very small in comparison to [H3O+], use following expression to calculate CH102] Сно, - к, СИә соз) ц, что о.озо Сно+) (-| xto-ч - о. І 2 х (о- м. оя е сол дау Снсо, 2- (K, о+) go'] = (Asco, L, L, . , Сно+)2 С (о ) 2 ч. |-II м ок, - е) мо*) - - Jej ( 1 xis") > 3.4 (c)