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The figure shows two long wires carrying equal currents 11 2.0 A and I2 3.0 A, flowing in opposite directions. At the locatio

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Answer #1

Magnetic force due to i1 = q v x B = 1.6e-19*3e7*2e-7*2/0.025

= 7.68*10^-17 N towards i1

Magnetic force due to i2 = q v x B = 1.6e-19*3e7*2e-7*3/0.025

= 11.52*10^-17 N away from i2

Net force = sqrt(7.68e-17^2 + 11.52e-17^2 + 2*7.68e-17*11.52e-17*cos 120 degree)

= 1.016*10^-16 N

direction = arccot((7.68 cos 60 degree + 11.52 cos 60 degree)/(7.68 sin 60 degree + 11.52 sin 60 degree))

= 19.1 degree below -x axis

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