Question

In the figure, suppose the length L of the uniform bar is 3.1 m and its weight is 190 N. Also, let the block's weight W = 250 N and the angle θ = 37°. The wire can withstand a maximum tension of 410 N. (a) What is the maximum possible distance x before the wire breaks? With the block placed at this maximum x, what are the (b) horizontal and (c) vertical components of the force on the bar from the hinge at A? col (a) Number X (b) Number (c) Numbe Click if you would like to Show Work for this question: UnitsT m UnitsTN Units TN Open Show Work SHOW HINT

Answer 1

a) sigma F_x = 0

F_x - T cos theta = 0

sigma F_y = 0

F_y - W_block - W_bar + T sin theta = 0

(T sin theta) L - W_block * d - W_bar * L/2 = 0

T = [ (T sin theta) L - W_bar * L/2 ] / W_block

= [(410 * 3.1 * sin 37) - (3.1/2 * 190)] / [250]

= 1.88 m

b) F_x = T cos theta = 410 * cos 37

horizontal component = 327.4 N

c) Fy = 190 + 250 - (410 * sin 37)

vertical component = 193 N