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Problem 22.33 < 6 of 8 > the 24-kg wheel is displaced a small amount and released. The radius of gyration of the wheel is kg

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mass moment of Inertia (I) = mk² =(24) (0-3892 = 3-4656 kgma Energy Stores! CE)= TEV - 10 + 2 k2? + 1/2 mua 4x3=4656 $? + X 5

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