Question

Q6 (a) A double stage compound gear system as shown in Figure Q6(a) has a meshing efficiency, n of 0.8 individually. Moment inertia of each shaft A, shaft B to C and shaft Dare 5 kg/m 30 kg/m' and 20 kg/m' respectively. Calculate the required motor power at input shaft to overcome the equivalent inertia given angular acceleration of motor is 10 rad/s? (10 marks)

Answer 1

First of all we need to find the equivalent moment of inertia with given efficiency of transmision.

Then we will find torque by using the inertia and given angular acceleration.

Hence power can be found by multiplication of torque and angular velocity.

Please be careful with the unit of moment of inertia given is wrong in the question.

The correct unit is . Kg.m^2

See the complete solution attached below.

Griven :- hillonsyropur (foumiffo buryson) 8:0=2 Jo 5 unit toun otac IBC = 30 unit It A 10 rad) seca motor Wmoto = 1500 rpm = 275x1500 rad 60 sec = 157.08 rad sec The equivalent moment of Inertia of the system is given as. por 2 Isai = JAT NA Mg J NA NB nc MD n² 2 5+ Jeq 30x200 20 200 20 20 X x + 80 200 250 0.82

Tega 5.425 unit Now Torque is given as T= I x. - 5.425 x 10 = 54.25 toan Hence Power = Tow - 54.25157008 Power 8521:59 watt