Question

ents and Stoichiometry: ME! 25. What is the limiting reagent if 0.200 g of maleic anhydride (MW 98.06) is reacted with 0.180 g of cyclopentadiene (MW 66.10), what is the limiting reagent? Use significant figures. Show your work. Just choosing an answer gets you zero credit. (5 points) U 0 a. maleic anhydride b. cyclopentadiene c. neither is limiting 26. How much cis-norbornene-5,6-endo-dicarbocylic anhydride (MW 164.16) can be produced? (10 points) a. 0.335 g b. 0.447 g c. 0.782 g d. 0.999 g

Answer 1

Q25. Correct answer is : (a.) maleic anhydride

Q25. Correct answer is : (a.) 0.335 g

Explanation

Q25. mass maleic anhydride = 0.200 g

moles maleic anhydride = (mass maleic anhydride) / (molar mass maleic anhydride)

moles maleic anhydride = (0.200 g) / (98.06 g/mol)

moles maleic anhydride = 2.04 x 10^-3 mol

mass cyclopentadiene = 0.180 g

moles cyclopentadiene = (mass cyclopentadiene) / (molar mass cyclopentadiene)

moles cyclopentadiene = (0.180 g) / (66.10 g/mol)

moles cyclopentadiene = 2.72 x 10^-3 mol

Since there are less moles of maleic anhydride, therefore, maleic anhydride is the limiting reactant.

Q26. moles of cis-norbornene-5,6-endo-dicarbocylic anhydride formed = moles maleic anhydride

moles of cis-norbornene-5,6-endo-dicarbocylic anhydride formed = 2.04 x 10^-3 mol

mass of cis-norbornene-5,6-endo-dicarbocylic anhydride formed = (moles cis-norbornene-5,6-endo-dicarbocylic anhydride formed) * (molar mass cis-norbornene-5,6-endo-dicarbocylic anhydride)

mass of cis-norbornene-5,6-endo-dicarbocylic anhydride formed = (2.04 x 10^-3 mol) * (164.16 g/mol)

mass of cis-norbornene-5,6-endo-dicarbocylic anhydride formed = 0.335 g