Question

Calculate the binding energy per nucleon of 45N in kJ/mol. The required masses (in g/mol) are: N 15.00011 g/mol H 1.00783 g/mol n 1.00867 g/mol kJ/mol nucleons

Answer 1

Beli 03) Actual mass of is n = 15.00011 gmoêl for Is N no. of Proton = 7 no. of neution = 15-7=8 Thus Theortical mass of 'N = 7xmass of proton of 8x mass of neuron. mass of proton lin) = 1600783g mot mass of neution (lan) = 1.00867 gmał Theortial mass of Theortical mass of 'SN N = 7 X 1.00783 +8x7.00867 = 7.054817 8.06936

NL Theortical mass of 'N = 15.12417 gmaz' m 2 mass defect como = Theortical mass - Actual mass mass defect com) = 15.12417-15.00011 = 0.2406gmoet Now mass defect com)= 0.12406gmo?' = 0u12406 LILIL + mass defect com) = 0.00012406 Kg moêl 1000 kg moel Now, Binding Energy = smc? : Here om=mass defect = 0.00019406 Kamoo Ca Speed of light = 3 x 108 mai

Sos Binding Energy = 0.0001246 Kg moê' x (3.x10mis) Binding Energy = 0.0001246 xq x 106 ky moēlm252 =) Binding Energy = 1.12148103 Kg m2 82 moet As IJ= 1 kg m² 82 => Binding Energy = 1.1214 x10smoł! no. of nucleons in 'n = no. of proton tho. of neation

23 = no. of nucleons in N= 7+8=15 so, Binding Energy per total Binding Enersy nucleony no of nuclears. . Binding Enessy per = 1.1214 x10² nucleons 15 :7.476 Xia!! & Binding Energy per = 7,476X10" I mae nucleons nucleons = 7.476X10" kg moêl nudeorus) Binding Energy per nucleons = 7476X10 Kj moel - nucleont'