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| arcsin(ln(I)) dx = In(2) a) ln(2) arcsin (In(2)) - V1 - (In(x))24 b) In (2) arcsin(In(2) . ln(2) TavI - (In(z)2 de c) O ln(

O + (anef ; (eorge Hoc @foܘܨ(f + ( P ܘܢ ,) +o ) ioo + ܕܡܨ(o t »nfoܨ,) ,) +o Hocܕܗܨ(*) ܗ,) +o S sinº (1) cos (2) dx =Please answer and state letter choice, will upvote

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Answer #1

are rinken (8) dx substitute Inexsay da-dy aresinful du Now use by parts u.arosincul- =147 dy In exl are tini &n (X) Inlog (I option (b) is the correct answer for both problems.

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