a) Option 1 the bottom of the hill.
Since we are going in a circular arc there must be one component
in the net force we are experiencing which points towards the
center of the circular arc and whose magnitude is mv^2/r. No
horizontal force contributes to mv^2/r.
The 30% heavier weight is actually just the magnitude of Fn. Since
we feel heavier we may compare this to upward acceleration of the
elevator. This means that we have some extra acceleration upward.
This extra part must be the ac=v^2/r, therefore the center of the
arc must be above our head
so we’re at the bottom of the hill.
b)
v = 90 km/h = 25 m/s
v^2/r = 0.30g
=> r = v^2/0.30g
=> r = (25)^2/(0.3*9.8)
=> r = 213m
You are traveling on a hilly road. At a particular spot, when your car is perfectly...
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