Given
Current I = 1.50 A
Inner radius of quadrant toroid a = 5.0 cm = 0.05 m
Outer radius of quadrant toroid a = 8.0 cm = 0.08 m
length of the quadrant toroid L = 2(a + b)/4 + 2(b - a) = 2(0.05 + 0.08)/4 + 2(0.08 - 0.05) = 0.2642 m
Now according to toroid, the magnetic field is given by
B = oI/L = (4x10-7x1.5x8/0.2642) = 7.1x10-6 Tesla
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