Solution :
2) Let X be a random variable which represents the birth weights.
Given that, X ~ N(7.6, 1.23²)
Mean (μ) = 7.6 pounds
SD (σ) = 1.23 pounds
We have to find P(X > 11.3 pounds).
We know that if X ~ N(μ, σ²) then,
Using "pnorm" function of R we get, P(Z > 3.0081) = 0.0013
Hence, the required probability is 0.0013.
2. Birth weights are normally distributed with a mean of 7.6 pounds and a standard deviation...
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