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5) The capacitor is initially discharged. The switch on the left side is closed for 2 seconds exactly and then opened. Immedi
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The voltage of the capacitor can be found by subtraction of voltages when it is charged and then discharged Switch on Solutions left Starts to charge v=Voe right side side is closed a is open Capacitor Vo = Intial voltage es exponent) سوره ها دور جم زرا Vex) = 300 x e .أ -Now right is closed left open: discharge Ks) = Voet (4) (470X10 X 10x10 = 121.31 x e - 41.86 V So Voltage = Vas - Yoj = 121-3

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