Question

120 110 100 90 80 902 3071 E 60 50 40 30 1446 20 1584 1023 21 N 10 1478 1085 2000 1500 1000 4000 3500 3000 2500 Wavenumbers (cm-1
The following is a neutral compound. Analyze proton NMR and IR to identify the unknown compound.

Answer 1

The IR spectra shows that:

The compound contains aromatic ring because the peak at 3071 cm-1 is due to aromatic C-H streching frequency.

Sharp peaks at 1584, 1478 and 1446 cm^-1 are due to aromatic C=C streching frequency.

1H - NMR shows that there is one one type of aromatic proton. The compound is neutral, Hence the possibility is that it is an aromatic hydrocarbon. The structure is: