Question

I need help interpreting this GC/MS spectrum, the product is suppose to be methyl 2-bromomethyl benzoate.

Radical bromination of methyl 2-methylbenzoate with N-bromosuccinimide and DCM was conducted to produce methyl 2-bromomethyl benzoate.

erator quired nstrument sample Nam Vial Numbe Abundance 140000 130000 20000 110000 Misc Info TIC: Gas A 2. Didata.ms 90000 80000 70000 60000 50000 30000 20000 10000 7.00 8.00-_9.00 10.00 11.00 Scan 417 (4.467 min): Gas A 2.Didata.ms 3.00 4.00 5.00-6.00 12.00- 13.00-. 14.00-15.00 160001 14000 12000 10000 8000 106 2000 51 63 65 103 84 74 86 89 53 45 50 55 60 65 70 75 80 85 9095 100 105 110 115

Answer 1

We can see 3 peaks. The one with highest abunndance is methyl 2-bromomethyl benzoate. There are 2 other products as well which have a higher m/z ratio. Both of these have less abundance than methyl 2-bromomethyl benzoate. These might be di substitued with bromine and thus have higher m/z ratio. Further these 2 among themselves are probably isomers because there m/z ratio is very close (103 & 106).