Question

A thin film of ??????2 has refractive index n = 1.38 and it is deposited on glass as an anti-reflective layer of light with wavelength 580nm that falls in the normal direction towards the film. What wavelength is minimally reflected when the light falls at 45 ° towards the film?

Answer 1

Igophere change 180 phere change hal .ch, <h2) h221-38 (h₂663) ₂21.5 The condition for deductive interfuence in tdeta (m+t) 1 (mari,2...) 212 (0+12) x 580mm 105.07 hm 2x138 h = 1 h221-38 As per mells law, to sin 45 = ha sin e =) One simt (hisous hz Ona in 1x din 45 30.82° 1.38 ta (mal) » 2n₂ for a beam incident at x = 212t (m+1) 45, 't will be d. a t 105.07 Conor 122.35 m. to) 30.82 X'z 2x1-38x 122-35 675.37 m. (0+12) Therefore, the wavelength which minimally reflects 675.37 km (when 0;= 45 )