Chapter 28, Problem 080
An electron in an old-fashioned TV camera tube is moving at 7.60 × 106 m/s in a magnetic field of strength 110 mT. What is the (a) maximum and (b) minimum magnitude of the force acting on the electron due to the field? (c) At one point the electron has an acceleration of magnitude 3.90 × 1014 m/s2. What is the angle between the electron's velocity and the magnetic field?
Chapter 28, Problem 080 An electron in an old-fashioned TV camera tube is moving at 7.60...
An electron in a TV camera tube is moving at 5.20×106 m/s in a magnetic field of strength 57 mT. Without knowing the direction of the field, what can you say about the greatest and least magnitude of the force acting on the electron due to the field? a) Maximum force? b) Minimum force? c) At one point the acceleration of the electron is 4.316×1016 m/s2. What is the angle between the electron velocity and the magnetic field? (deg)
An electron in a TV camera tube is moving at 7.20×106 m/s in a magnetic field of strength 65 mT. Without knowing the direction of the field, what can you say about the greatest and least magnitude of the force acting on the electron due to the field? Maximum force? Submit Answer Tries 0/99 Minimum force? Submit Answer Tries 0/99 At one point the acceleration of the electron is 7.509×1016 m/s2. What is the angle between the electron velocity and...
A proton, moving at a velocity of 681 m/s experiences an acceleration of 2.0 x 1014 m/s2 when it enters a magnetic field at an angle of 55 degrees to the field. Calculate the strength of the magnetic field. Assume that the force from the magnetic field is the only force acting on the proton. (Hint: You will need to solve for this force first!)
14. (7 pts) An electron in an old-style television picture tube moves toward the front of the tube along the x axis as shown. Surrounding the neck of the tube are coils of wire that create a magnetic field of magnitude 0.025 T, directed at an angle of 60° to the x axis and lying in the xy plane. What is the speed of the electron if the magnetic force acting on it is found to be 2.8 x 10...
An electron is accelerated through 2,500 V from rest and then enters a region where there is a uniform 1.80 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron? (a) maximum (b) minimum Need Help? LAeadn OIL wenn 8.-12.5 points SerCP10 19 P.009 MI.FB My Notes Ask Your Te A proton moving at 7.60% 106 m/s through a magnetic field of magnitude 1.72 T experiences a magnetic force of magnitude 7.60%...
Chapter 28, Problem 003 An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.3 × 106 m/s moves through a uniform magnetic field with x component 0.033 T and y component -0.17 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity (a) Number (b) Number Click if you would like to Show Work for this question: Open Show Work...
An electron is moving at a speed of 2.40 109 m/s in a circular path of radius of 4.1 cm inside a solenoid. The magnetic field of the solenoid is perpendicular to the plane of the electron's path. The solenoid has 25 turns per centimeter. (a) Find the strength of the magnetic field inside the solenoid. AT (b) Find the current in the solenoid. mA Additional Materials eBook -/1 Points) DETAILS SERCP10 20.P.001. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER...
Chapter 28, Problem 009 In the figure, an electron accelerated from rest through potential difference V1-1.00 kV enters the gap between two parallel plates having separation d- 23.1 mm and potential difference V2 167 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the...
Chapter 28, Problem 004 An alpha particle travels at a velocity of magnitude 800 m/s through a uniform magnetic field of magnitude 0.047 T. (An alpha particle has a charge of charge of +3.2x 1019 C and a mass 6.6 x 10-27 kg) The angle between the particle's direction of motion and the magnetic field is 61°. What is the magnitude of (a) the force acting on the particle due to the field, and (b) the acceleration of the particle...