Question

7. (10 pts pt.) A 20 turn rectangular coil with sides of length in 30 cm and width w 10 cm is placed in plane as shown in Figure below a. If the coil, which carries a current i = 10 A is in the presence of a magnetic flux density B = 2x10 (+92) (Tesla) Determine the torque acting on the coil. b. At what angle is the torque zero? c. At what angle is the torque maximum? Determine its value 20-tum coil Hint ñ = coso + ŷ sind

Answer 1

Griven Data & A 20 tum rectangular coil with sides l=30cm and w=10cm is placed in the y z 71 leto plane as shown. magnetic moment of loop M = NIA so ñ - (20)(10) (0103) â, so m a cân in makes & angle with x-axis the @ we have to find is in the presence of a magnetic Flux density - b = 2 xlo” (x ++) it the coil, which carries a Curresit I=10 A. we have to determines the torque alling on the coil. Torque is a measure of the force that can Cause an object to rotate about am aris. Just as Force is what causes object to accelerate in Linear Kinematics. Torque acting on coil is given by TE MB | So ITI = |1 x 81 8% (Angle blao 3 x 3) Let angle b/w M & B Ome So 17 1= ln 1151 sinOMB 171 - 6x6.044 SinOMB 171 = 0.26 SinouB

③ we have to find the angle & Torasue is zero when one is a zero cor) 188. So Both aneb should comide . 4,=634 •, -63.4 in may be just 180 from a t. This gives the possiblity 402 42 = 180+ 63.4 . 2 243.49 @ we have to find at what angle of is the torque manimum. torque is maximum when the angle is 90°. a practicle way to calculate the magnitude of the torque is to first determi -ne the lever arm and then multiply it times the applied Force. 63.4 - 6290 1 62-63-4 = 90° 18, = -26.59 I 142 = 153.4) There are two possible values . ↑ of & for which torqine is est possibility monimum but main this is that A T angle blom E B should be a 98 for monimum torque & Pondpossi A 65.4