Question

The United States ranks ninth in the world in per capita chocolate consumption; Forbes reports that the average American eats 9.5 pounds of chocolate annually. Suppose you are curious whether chocolate consumption is higher in Hershey, Pennsylvania, the location of the Hershey Company's corporate headquarters. A sample of 33 individuals from the Hershey area showed a sample mean annual consumption of 10.05 pounds and a standard deviation of s = 1.5 pounds. Using a = 0.05, do the sample results support the conclusion that mean annual consumption of chocolate is higher in Hershey than it is throughout the United States? State the null and alternative hypotheses. (Enter != for # as needed.) Hoi Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) -value = State your conclusion. Reject H. We cannot conclude that mean annual consumption of chocolate in Hershey is greater than mean annual consumption of chocolate throughout the United States. Do not reject Ho. We cannot conclude that mean annual consumption of chocolate in Hershey is greater than mean annual consumption of chocolate throughout the United States. Do not reject Ho. We can conclude that mean annual consumption of chocolate in Hershey is greater than mean annual consumption of chocolate throughout the United States. Reject H. We can conclude that mean annual consumption of chocolate in Hershey is greater than mean annual consumption of chocolate throughout the United States.

Answer 1

The statistical software output for this problem is :

One sample T summary hypothesis test: u: Mean of population Ho:u=9.5 HA: > 9.5 Hypothesis test results: Mean Sample Mean Std. Err. DF T-Stat 10.05 0.26111648 32 2.1063396 P-value 0.0216

H₀ : μ = 9.5
H_A : μ > 9.5

Test statistics = 2.106

P-value = 0.0216

Option D is correct