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Suppose a 1.5 cm tall object is placed 3.50 cm in front of a diverging lens...

Suppose a 1.5 cm tall object is placed 3.50 cm in front of a diverging lens with focal length -2.00 cm. Draw a ray diagram that accurately shows the image.

A) The image is { a. upright b. inverted }.

B) The image is { a. real b. virtual }.

C) The image position is a. -0.3502 cm d. -1.569 cm b. 0.5616 cm e. -1.273 cm c. -0.3788 cm f. -1.257 cm

D) The magnification is a. -0.3709 d. 0.07389 b. 0.3636 e. 0.1458 c. -0.3701 f. -0.1853

E) The height of the image is a. 0.2376 cm d. -0.1448 cm b. 0.5455 cm e. 0.3569 cm c. -0.1172 cm f. -0.4494 cm

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Answer #1

(a0 Upright

(B) Virtual

(C) Ans(E)

D. ans(B)

E. ) Ans(b)

1/f = 1/p + 1/q

1/-2 = 1/3.5 + 1/q

q = - 1.273


m= - q/p = 1.273 / 3.5 = 0.3636

h = 1.5 x 0.3636 = 0.5455 cm

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