Question

Say a 95% confidence interval for P2 - P2, the difference between two proportions, is (0.152, 0.392). This indicates that the difference between the two proportions is not significant. A) True-- Yes OB) False--No O C) Can't tell without the data Question 7 (1 point) According to National Eye Institute (NEI), in 2010, 61% of Americans with cataract were women and 39% were men. Suppose you want to conduct a test for the difference in proportions to test whether females (F) are more likely to have cataract than males (M). What are the appropriate hypotheses for this test? OA) Ho: P-PM0, HA: PF - PM = 0 OB) HP- PM <0, HA: PF - PM20 OC) Ho: HS0, Ha: >0 OD) Họ: P - P < 0, HN: PE -PM > 0 E) HP - PMSO, HA: P: - PM > 0

Answer 1

Correct Option is highlighted:

Say a 95% confidence interval for p. - P2, the difference between two proportions, is (0.152, 0.392). This indicates that the difference between the two proportions is not significant. OA) True--Yes OB) False--No O C) Can't tell without the data

Explanation: Since confidence interval does not contain zero, the difference between the two proportions is significant.

Answer 7:

Correct option is highlighted:

OA) Ho: PF - PM+ 0, HA: PF - PM = 0 B) H: PF - PM<0, HA: PF - PM20 OC) Ho: U SO, HA: 4>0 OD) Ho: És – ÔM SO, HA: És - Ôn > 0 E) Ho: P: - PM SO, HA:P: - PM > 0

Explanation: In this case, we have to test that females are more likely to have cataract than males. In other words, we need to test p_f - p_m > 0. Thus, Option E is correct.

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