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Question 15 (2 points) ✓ Saved The molecular model for Propylene glycol is shown below. What is its empirical formula? carbon
Question 16 (2 points) Saved If X form the compound XSO4 with sulfate ion, what compound does it form with Cl? OA) XC13 B) X
Question 19 (2 points) ✓ Saved The ion with a charge of +3 and 25 electrons, is an ion of the element? a. Mn b. Ni C. Ti d. F
Question 22 (5 points)* Saved A stainless steel rod has a density of 7.75 g/cm3 and a diameter of 2.54 cm. If we want a 1,000
Question 23 (2 points) ✓ Saved I have equal volumes of each of the metals given below. Which of the sample will have the larg
Question 24 (2 points) Saved Which of the following equations best represents the reaction shown in the diagram? B B A) 3A +

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Answer #1

1. By counting the number of atoms of each element in the molecular model, we get the molecular formula. An empirical formula is the simplest ratio of all the elements in the compound. When the common factor is taken out of the molecular formula, we get the empirical formula.

The molecular formula of the given model is: C3H8O2

3, 8, and 2 do not have any common factor. So here, empirical formula = molecular formula.

Thus, empirical formula = C3H8O2 (B)

2. Sulfate ion has a charge of 2-. As XSO4 is a neutral compound, that means X has a charge of 2+ (X2+). Now, by criss-cross method, the formula with the chloride would be XCl2 (D).

3. The ion has 25 electrons and a charge of +3. This means the ion has lost 3 electrons.

So, number of electrons in the neutral atom = 25 + 3 = 28

For a neutral atom, atomic number = number of protons = number of electrons = 28

The atom with atomic number 28 is nickel (Ni). Thus, the given ion is an ion of Ni (D).

4.

Given,\\ Density\ of\ the\ rod\ (D)= 7.75\ g/cc\\ Diameter\ of\ the\ rod\ (d) = 2.54\ cm\\ Mass\ to\ be\ cut\ (M)=1000\ g\\ So,\\ Density=\frac{Mass}{Volume}\Rightarrow D=\frac{M}{V}\Rightarrow 7.75\ g/cc = \frac{1000\ g}{V}\Rightarrow V =\frac{1000\ g}{7.75\ g/cc}=129.03\ cc\\ A\ rod\ is\ cylindrical\ object\ and\ volume\ of\ cylinder=\pi r^2h = \pi \frac{d^2}{4}h\\ Fomr\ the\ above\ two\ equation,\ we\ get\\ \pi \frac{d^2}{4}h=129.03\Rightarrow (3.14)(\frac{2.54^2}{4})h=129.03\\ \Rightarrow h=\frac{129.03\times4}{3.14\times 2.54\times 2.54}=25.48\ cm\\ \bold{25.48\ cm\ would\ be\ cut\ out\ from\ the\ rod.}

5. Density=\frac{Mass}{Volume}

All the metals given have equal volumes. So, the mass would directly depend on the density. The metal having the highest density will have the highest mass.

Out of the given metals, platinum has the highest density (21.3 g/mL). So, it has the highest mass.

Thus, platinum (21.3 g/mL) (A) will have the highest mass.

6. In the given diagram, 6 atoms of A combine with 4 atoms of B to form 4 atoms of C and 2 atoms of D. This can be represented in the form of a chemical equation as

6A + 4B --> 4C + 2D

Or, taking the common factor (2) out, 3A + 2B --> 2C + D.

So, (A) is the correct answer.

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