The excel macro output for this problem is:
Hence,
95% confidence interval will be:
123.663 233.922
A student was performed on a type of bearing to find the relationship of amount of...
ny = 11 X1 = 13 1 The following data represent the length of time, in days, to recovery for patients randomly treated with one of two medications to clear up severe bladder infections. Find a 95% confidence interval for the difference H2 – My between in the mean recovery times for the two medications, assuming normal populations with equal variances. Medication 1 s = s = 1.9 Medication 2 X2 = = 18 sz S. = 1.1 Click here...
A taxi company is trying to decide whether to purchase brand A or brand B tires for its fleet of taxis. To estimate the difference in the two brands, an experiment is conducted using 13 of each brand. The tires are run until they wear out. The results are given in the table below. Compute a 95% confidence interval for HA-Ha assuming the populations to be approximately normally distributed. You may not assume that the variances are equal Brand A...
If X=95, S =5, and n = 49, and assuming that the population is normally distributed, construct a 99% confidence interval estimate of the population mean, u. Click here to view page 1 of the table of critical values for the t distribution. Click here to view page 2 of the table of critical values for the t distribution. (Round to two decimal places as needed.)
Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn. x overbarxequals=2.0 nequals=51 sequals=4.5 confidence levelequals=95% Click here to view page 1 of the table of critical values for the t distribution. LOADING... Click here to view page 2 of the table of critical values for the t distribution. LOADING... The 95% confidence interval...
X 9.9.43 Question Help A taxi company is trying to decide whether to purchase brand A or brand B tires for its fleet of taxis. To estimate the difference in the two brands, an experiment is conducted using 16 of each brand. The tires are run until they wear out. The results are given in the table below. Compute a 95% confidence interval for u. He assuming the populations to be approximately normally distributed. You may not assume that the...
In a survey of 1006 adults, a polling agency asked, "When you retire, do you think you will have enough money to live comfortably or not. Of the 1006 surveyed, 531 stated that they were worried about having enough money to live comfortably in retirement. Construct a 95% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement. Click here to view the standard normal distribution table (page 1). Click here...
If X-67, S-20, and n-49, and assuming that the population is normally distributed, construct a 99% confidence interval estimate of the population mean, μ Click here to view page 1 of the table of critical values for the tdistribution Click here to view page 2 of the table of critical values for the t distribution (Round to two decimal places as needed.)
If X = 70, S = 9, and n= 36, and assuming that the population is normally distributed, construct a 99% confidence interval estimate of the population mean, u. Click here to view page 1 of the table of critical values for the t distribution. Click here to view page 2 of the table of critical values for the t distribution. (Round to two decimal places as needed.)
A taxi company is trying to decide whether to purchase brand A or brand B tires for its fleet of taxis. To estimate the difference in the two brands, an experiment is conducted using 8 of each brand, assigned at random to the left and right rear wheels of 8 taxis. The tires are run until they wear out and the distances, in kilometers, are recorded in the accompanying data set. Find a 95% confidence interval for H, - Hy....
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An advertising executive wants to estimate the mean weekly amount of time consumers spend watching traditional television daily. Based on previous studies, the standard deviation is assumed to be 23 minutes. The executive wants to estimate, with 99% confidence, the mean weekly amount of time to within + 6 minutes. a. What sample size is needed? b. If 95% confidence is desired, how many consumers need to be selected? a. The sample size required for...