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Test: Final This Question: 6 pts Use an appropriate substitution and then a trigonometric substitution to evaluate the integr
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Answer #1

I= Put x = x= 3 seco dx= 3Seco tano de x3 g = a sec²0-9= 9 (Sec²0-)) -a tanzo S v se za 3 tano I= 3 seco tano do 3Seco (3 tan

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Answer #2


ANSWER :


Substitution : Option C :  x = 3 sec θ. (ANSWER)


=> dx = 3 sec θ tan θ dθ  (ANSWER)



∫ dx / (x sqrt(x^2 - 9)) 


Using the above substitution , the given integral is :


=  ∫  3 sec θ tan θ dθ / (3 sec θ * sqrt (9 sec^2 θ - 9) )


= ∫ 3 sec θ tan θ dθ / (3 sec θ * 3 tan θ)


= ∫ dθ/3


= θ/3 + C 


= 1/3 * sec ^(-1) (x/3) + C      (ANSWER).







answered by: Tulsiram Garg
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