Question

A professional boxer hits his opponent with a 1160 N horizontal blow that lasts 0.180 s. The opponent's total body mass is 112 kg and the blow strikes him near his center of mass and while he is motionless in midair. Determine the following. the impulse the boxer imparts to his opponent by this blow kg middot m/s the opponent's final velocity after the blow m/s Calculate the recoil velocity of the opponent's 5.00 kg head if hit in this manner, assuming the head does not initially transfer significant momentum to the boxer's body. m/s

Answer 1

F = 1160 N
t = 0.180 s

(a)
Impulse boxer imparts to his opponent = F * t
I = 1160 * 0.180
I = 208.8 kg m/s

(b)
F.t = m*v
208.8 = 112 * v
v = 1.86 m/s

(c)
Using Momentum conservation,
5 * Vrc = 112 * 1.86
Vrc = 41.6 m/s