Give one benefit of having small time quantum and one benefit of having large time quantum in Round Robin Scheduling.
benefit of having small time quantum in round Robin is all large processes equally complete their execution and efficient response time improved.Benefit of having large quantum time in round Robin is small processes complete their execution in less time.
if any queries please comment me.
Give one benefit of having small time quantum and one benefit of having large time quantum...
Solve by Round Robin Scheduling, Quantum = 3 (preemptive). Calculate the average waiting time: Process Arrival Time Execution Time РО 5 P1 1 3 P2 N 8 P3 3 6
Round Robin Schedulin ProcessBurst Time in MsP14P22P32Calculate the average waiting time and turnaround time using round robin scheduling, where the time quantum q = 2 ms According to the Round Robin algorithm, the arrival of processes is shown in the following Gantt chart. From the Gantt chart, the waiting time and the turnaround time are calculated as: Waiting time for P1= Waiting time for P2 = Waiting time for P2 = Therefore, the average waiting time = Turnaround time =
6. Draw GANTT charts (plots of activity vs. time) for the Round Robin and Priority scheduling strategies for the following jobs (assume larger numbers mean higher priority and that the time quantum is 2): (10 marks ) Job Arrival Time Duration Priority tam What is the average waiting time under each scheme? Time → Average wait time for round robin is: PRIORITY Time → Average wait time for round robin is:
Five batch jobs (A,D,I,J,K) arrive at a computer at the same time(at time=0). The quantum size of this system is 2 units of time. For each of the scheduling methods given below, calculate the average waiting time for the 5 jobs. Show (use timing diagrams) and explain your steps. You can prepare it by hand or on a computer. The following jobs and the estimated running times are defined: A 2 B 6 C 4 D 8 E 2 F...
Consider the set process. There arrival time start from 0, Consider your seat number as burst time also consider all time value in seconds. Find average time of following Scheduling Algorithm. Note (quantum=2) (a) Longest Remaining time first (LRTF) (Preemptive) (b) Round Robin Scheduling (LRTF) (Non- Preemptive)
4. Consider a ready queue with four processes :- Process Arrival Time Burst Time (ms) P1 Priority P2 P3 P4 P5 For each of the following CPU scheduling algorithms, determine the turnaround and average waiting time for each of the process :- a. Shortest remaining Time First b. Shortest Job First C. Priority Scheduling (Both pre-emptive and non-preemptive) d. Round Robin (quantum is 1 ms)
The question is this. there is nothing given [8 What is the waiting time of each process for each of the scheduling algorithms? Marks] Job Arrival Time Size (msec) P1 0 9 Priority 3 (Silver) 1 (Diamond) 3 (Silver) P2 3 P3 3 3 P4 6 5 4 (Bronze) 2 (Gold) P5 7 4 (a) First-Come-First-Served (FCFS) scheduling (b) Preemptive PRIORITY scheduling (c) Non-preemptive PRIORITY scheduling (d) Round Robin (RR) (quantum = 3) scheduling
What is a solution to the problem of having a deadlock in a Round Robin scheduling system
Q2. Consider the following processes with arrival time and burst time. 20 Marks Process Arrival Time Burst Time P16 29 0.0 P21 19.0 12 P32 22.0 13 P41 30.0 25 Calculate waiting time and average waiting time Round Robin (R-R) scheduling algorithm by using the following Quantum/Time slice: a. Quantum/Time Slice = 8 b. Quantum/Time Slice = 16 Q3. Calculate the CPU Utilization and Idle time by considering 35% I/O wait and number of processes are from 1 to 5....
Can you please choose the correct answer arrival time Bust time pl for the above table, under FCFS scheduling, processes are scheduled as follows: a. pl, p4, p2, p3 b. pl, p2, p4, p3 c. pl, p2, p3, p4 d. p2, p4, p3, pl arrival time Bust time 13 for the above table, under SJF scheduling, processes are scheduled as follows c. d. p3, pl, p4, p3 X pl, p3, p4, p2 pl, p3, p2, arrival time Bust time 13...