A device used in radiation therapy for cancer contains 0.17 g of cobalt-60 (59.933 819 u). The half-life of this isotope is 5.27 yr. Determine the activity (in Bq) of the radioactive material.
half life = ln(2)/k
k = ln(2)/half life = ln(2)/(5.27 x 365 x 24 x 3600) = 4.170693152 x 10-9 /s
now no. of molecules = (0.17/59.933819) x 6.023 x 1023 = 1.708401062 x 1021
activity = 4.170693152 x 10-9 x 1.708401062 x 1021 = 7.12521661 x 1012 Bq
A device used in radiation therapy for cancer contains 0.17 g of cobalt-60 (59.933 819 u)....
A device used in radiation therapy for cancer contains 0.25 g of cobalt-60 (59.933 819 u). The half-life of this isotope is 5.27 yr. Determine the activity (in Bq) of the radioactive material. Provide units please
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A device used in radiation therapy for cancer contains 8.00x10-1 g of cobalt 2760 Co (59.9333819 u). The half-life of 2760 Co is 3.47 yr. Determine the activity of the radioactive material. Submit Answer Tries 0/10 This discussion is closed. 45
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