Question

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19. Calculate the wavelength, in nm, of an electromagnetic radiation with a frequency 835.6 MHz (common frequeney used for cell phone communication). (c 3.0 x 10* m/s, h-6.6262 x 103 J.s). 1Pt.) 20. A laser pulse with wavelength 532 nm contains 4.67 mJ of energy. How many photons are in the laser pulse? (c 3.0 x 108 m/s, h 6.6262 x 103* J.s). Ans.: 21. An electron in the n 7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 397 nm. What is the value of n for the level to which the electron relaxed? 22. Write the ground state electron configurations of the following atomsions: a) Se2: 23. Indicate the number of unpaired electrons the following cations have in the ground state a) Cd2*: b) Rh2+

Answer 1

19. 3.590×10^8 nm

20. 1.25×10^25 photon

21. The electron relax to n= 2

22.

23. a) number of unpaired electron in Cd2+ is zero(0)

b) number of unpaired electron in Rh3+ is three(3)