Answer:
It will go to interface 1.
Mask is of 22, means last 10 bits
are for host id and 1st 22 bits are for netid. So ur mask becomes
22 1's followed by 10 0's. As 10 bits are involved, so it is enough
to check the last 2 octets. So ur last 2 octets of mask n given ip
are:
11111100.00000000
00111111.00001010
Bitwise ANDing them, we get
00111100.00000000 -> 60.0
That's it, it matches with interface 1.
A router has the following CIDR entries in its routing table: Address/mask 128.56.24.0/22 128.56.60.0/22 default Next...
A router has the following CIDR entries in its routing table: Address/mask 135.46.56.0/22 135.46.60.0/22 92.53.40.0/23 default Next hop Interface 0 Interface 1 Router 1 Router 2 What does the router do, if a packet arrives with each of the destination addresses given below? a. 135.46.63.10 b. 135.46.57.14 c. 135.46.52.2 d. 192.53.40.7 e. 192.53.56.7
A router has the following (CIDR) entries in its routing table: Address/mask 135.46.56.0/22 135.46.60.0/22 92.53.40.0/23 Router 1 Next hop Interface 0 Interface 1 For each of the following IP addresses, what does the router do if a packet with that address arrives? Explain your answer and provide details of your response. (a) 135.46.63.10 (b) 135.46.57.14 (c) 192.53.40.7
1. (IP Forwarding) A router has the following entries in its routing table Address/mask 135.46.56.0/22 135.46.60.0/22 192.53.40.0/23 0.0.0.0/0 Next hop Interface 0 Interface 1 Router 1 Router 2 For each of the following IP addresses, what does the router do if a packet with that address arrives? (a) 135.46.63.10 (b) 135.46.57.14 (c) 135.46.52.2 (d) 192.53.40.7 (e) 192.53.56.7
5. A router has the following CIDR entries in its routing table Address/mask 135.46.0.0/16 135.46.60.0/24 135.46.80.12/32 192.53.40.0/24 192.53.40.7/32 0.0.0.0/0 (default) RoterF Next hop Router A Router B Router C Router D Router E For each of the following IP addresses, list all the matching targets first, and then indicate which match is chosen and explain why a) 135.46.60.10 b) 135.46.57.14 c) 135.46.80.18 d) 192.53.40.7 e) 192.53.56.7
CIDR. The table below is a routing table using Classless Interdomain Routing (CIDR). Address bytes for the subnet number as well as the subnet mask are h hexadecimal notation. Thus, the subnet number 128.46.101.0 is represented as 80.2E.65.0 and the subnet mask 255.255.255.0 is represented as FF.FF.FF.0 Next Hop Subnet Number C4.5E.40.0 C4.5E.4F.0 C4.50.0.0 C4.5E.0.0 Default Subnet Mask FF FF F0.00 FF FF.FF.00 FF F0.00.00 FF FF.00.00 State to what next hop a packet for the following destination IP addresses...
Question 6 A router has the following routing table: Destination Address Range Link Interface 123.46.56.0/22 1 123.46.56.0/23 2 123.46.56.0/24 3 Otherwise 4 The router uses longest-prefix matching. On which interface will the router send each of the following received packets: Packet 1 with a destination: 123.46.56.1 Packet 2 with a destination: 123.46.56.2 Packet 3 with a destination: 123.46.56.3 Packet 4 with a destination: 123.46.56.4
Row Network/Subnet 0.0.0.0 1 128.171.0.0 172.30.33.0 Mask (/Prefix) Metric (Cost) Interface Next Hop Router 0.0.0.0 (/0) 255.255.0.0/16) 47 255.255.255.0 (/24) Local 255.255.255.0/24) 12 255.255.255.0 (/24) 55 255.255.255.0 (/24) 34 Local 255.255.255.0 (/24) 20 192.168.6.0 128.171.17.0 172.29.8.0 172.29.8.0 For the routing table above, if the arriving packet has a destination IP address 128.171.17.56, it will match with row 1 5 3
Classless Inter-Domain Routing (CIDR) is a method for allocating IP addresses and routing Internet Protocol packets. Classless Inter-Domain Routing allocates address space to Internet service providers and end users on any address bit boundary, instead of on 8-bit segments. CIDR notation is a syntax of specifying IP addresses and their associated routing prefix. It appends a slash character to the address and the decimal number of leading bits of the routing prefix. 192.168.100.0/24 represents the given IPv4 address and its...
A router that has the routing table in Figure 8-11 receives an incoming IPv4 packet. The source IPv4 address in the arriving packet is 10.55.72.234. The des-tination IPv4 address is 10.4.6.7. The TTL value is 1. The Protocol Field value is 6. What will the router do with this packet? (Hint: Carefully consider all the fields in the IP and TCP headers. Think like a router.)
with explanation please Answer the following: 140.24.7.0/26 170.14.0.0/16 140.24.7.5 170.14.5.165 180.55.0.0/16 140.24.7.64/26 m1 m3 140.24.7.78 R1 mo R2 180.55.100.30 m2 180.55.60.14 mo m3 145.80.7.11 190.220.44.67 140.24.7.128/26 140.24.7.130 145.80.0.0/16 Rest of Internet a) Find the routing table for router R1. Mask Network Address Next hop Interface b) Find the routing table for router R2. Mask Network Address | Next hop Interface c) A packet arrives at router R1 with destination address 145.80.14.26. Show how it is forwarded. d) A packet arrives...