Preamble From A,Gº = -1FE® and A, Sº =-("), it follows immediately that A, Sº =...
Help with B. and C. please. 4.) (a.) ( 3pts) T = 298 K: Calculate AE® and AG" for the following reaction: 4Cytochrome (Fe) + O2+ 4H-4Cytochrome (Fe) + 2H20 Cytochrome c(Fe 3) + e - Cytochrome c(Fe 2) Eº = 0.254 V Donor 1/202 +2e +2H-H2O E' = 0.815 V Acceptor AE°) = 0.815 V-o.a54V) = 0.561V AG") = -2(96.5)(0.561 V) = -108.273 kJ/mol (b.) (2 pts) What enzyme catalyzes the above reaction? (c.) (3 pts) It takes 20...
Consider the following reaction at 298K. 2 Cr3+ (aq) + 2 r (aq) →→2 Cr2+ (aq) + 12 (8) Which of the following statements are correct? Choose all that apply. n=4 mol electrons delta Gº < 0 OK<1 Eºcell < 0 The reaction is product-favored. Consider the following reaction at 298 K. 3 Fe3+ (aq) + Cr(s) – → 3 Fe2+(aq) + Cr3+(aq) Which of the following statements are correct? Choose all that apply. OK<1 n= 3 mol electrons E°...
please help answer question 4, a-f please using the data below from chart 1 objectives from lab, thank you DATA:CA y 3 Ay No3 Part I: Cell Potential of voltaic cells under standard conditions: cell CU CND2 #27 14.0m Give the half Half cell reaction at Combinations Oxidation Reduction E the anode and with [ion] takes place Theoretical takes place cathode. Write in M here here (V) above the arrow E c (V) if it is oxidation or reduction. |-0.340...