Investigate the following IR Absorption, 13C and 1H NMR below:
Compound X's IR (BELOW)
Compound X's 13C NMR (BELOW)
Compound X's 1H NMR (BELOW)
1. Investigate the diagnostic IR Absorption of compound X shown above and use this to determine the functional groups present. Use a table that goes (as an example):
(EXAMPLE ONLY)
Frequency (cm-1) | Relative Intensity or Shape | Vibrational Assignment |
2950 | Medium | C-H Stretch |
1715 | Sharp and Strong | C double bond O Stretch |
2. Investigate the 1H and 13C NMR data of compound X shown above and use this to determine the carbon-hydrogen framework of the molecule. Use a table that goes (as an example):
(EXAMPLE ONLY)
Carbon Number | Observed, (parts per million) | Assignment | Expected Chemical Shift, (parts per million) |
C1 | 40 | CH2-O | 40-50 |
(EXAMPLE ONLY)
Hydrogen Number | Integral | Signal Multiplicity | Exptl. (parts per million) | Assignment | Expected Chemical Shift, (parts per million) |
H1 | Triplet | 1.32 | CH3C-O- | 1.2 |
Present the most likely structure based on the IR Absorption, 1H and 13C NMR data to support your case. If there is more than one compound that fits the data provided, present all the structure of the compound.
Investigate the following IR Absorption, 13C and 1H NMR below: Compound X's IR (BELOW) Compound X's...
Evaluate and investigate the following IR Spectrum and 1H NMR Spectrum. Identify the most important peaks and correlate the results as much as you can from the obtained product in the multi-step synthesis of ethyl acetoacetate. This is Product C from this multi-step synthesis where Product B was identified as in the figure below and as such, identify what product can be obtained after the synthesis from the spectra provided. Use the template below in analysing the spectra. Figure 1...
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On the attached image are 1H NMR, 13C NMR, and IR spectra of a compound with the formula C4H8O. 1H NMR signal at 1.2 is caused by 3 hydrogens, the sigbal at 2.1 is caused by 3 hydrogens, and the signal at 2.5 is caused by 2 hydrogens. Identify the compound. CH 1110 9 8 7 6?4 Problem 6. 'H NMR spectrum of compound HsO Problem 6. 13C NMR spectrum of compound C4HsO 200 180 160 140 120 100 80...
for the following 2 compounds, please calculate, and show the calculations for, the degree of unsaturation, assign the IR spectrum peaks, assign the 13C NMR peaks, assign the 1H NMR peaks, and draw the structure for the unknown compound. CHIM 245 Spectroscopy Problem Set #2 In this problem set there are two unknown compounds. You are provided with the formula, IR spectrum, "C NMR spectrum, and 'H NMR spectrum for each compound. Each unknown is worth 10 points, with an...
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A compound with molecular formula C11H140 displays the following IR, 1H NMR and 13C NMR spectra. Propose a structure for this compound. Ppin 220.200.180.160.140 120 PPM 100 80 60 40 20
Compound 2: Use the information provided below and the IR and NMR spectra on the next page to answer the following questions. a) An MS was taken of compound 2 and the table is given below. Determine the molecular formula of 2 from the MS given below relative abundance m/z 132 100 133 9.8 b) Calculate the Index of Hydrogen Deficiency/Degree of Unsaturation for the molecule. c) Using the IR spectrum and the 1H- and 13C-NMR spectra given below, determine...
Using IR spectrum and 1H and 13C NMR spectra to figure out what the unknown compound is C: 63.15 H: 5.30 7.0 6.5 4,5 4.0 MW 152.149 12. Ola C
What is the structure of unknown compound based on 1H and 13C NMR and IR Spectra BRUKER 3500 3000 2500 2000 Wavenumber cm-1 1500 1000 500 C1OPUS 65)MEASIGB Product 20 GB Product 2 Instrument type and / or accessony 01/03/2018 Page 1/1
A compound with molecular formula C7H160 displays the following IR and 'H-NMR spectra. The 13C NMR data suggest that there is some symmetry within the molecule. a) Calculate the degrees of unsaturation (DU) for the compound in the space provided below. DU = b) Identify and label the two indicated peaks in the IR spectrum in the boxes provided. Identify and label ALL peaks in the 'H NMR spectrum below. The numbers given on the 'H NMR are integration values...