Calculate the voltage you would anticipate for a cell that includes the titration of 50.00 mL...
Calculate the voltage you would anticipate for a cell that includes the titration of 50.00 mL of 0.133 M Cl with 0.100 M Ag after 24.27 mL of the silver had been added. The indicator electrode is a silver wire and the reference electrode is silver-silver chloride (in saturated KCl).
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Calculate the voltage you would anticipate for a cell that
includes the titration of 50.00 mL...
0. (15 points) An analytical chemist conducted the titration of 50.00 mL of 0.100 M Ag...
0. (15 points) An analytical chemist conducted the titration of 50.00 mL of 0.100 M Ag using 0.150 M CT solution. Silver wire is the indicator electrode and the saturated Ag-AgCl electrode is the reference electrode. E = 0.197 V for the saturated Ag-AgCl electrode, EºAg+/Ag= 0.1993 and Ksp = 1.8 x 10-8 for AgCI a) Calculate E at the volume of Cl' is 25.0 mL. Show all your work. b) Calculate E at the volume of Cl' is 50.0...
please answer the following question 2. Calculate E for the titration of 48.00 mL of 0.110...
please answer the following question
2. Calculate E for the titration of 48.00 mL of 0.110 M Ag when 50.00 mL of 0.140 M Cl" is added. Silver wire is the indicator electrode and the saturated Ag-AgCl electrode is the reference electrode. E=0.197 V for the saturated Ag-AgCl electrode, E.= 0.7993 V and Ksp = 1.8 10- for AgCl.
i answered 0.58 but I got it wrong. can you help/solve? Question: A chemist measures the...
i
answered 0.58 but I got it wrong.
can you help/solve?
Question:
A chemist measures the potential of an electrochemical cell
vs. the saturated calomel electrode to be +0.5V. Then, the chemist
switches the reference electrode to the silver-silver chloride
electrode.
What should the voltage read?
Use the following diagram to assist your thought
process:
Previously we discussed a calomel reference electrode. A second type of reference electrode is also very common in lab - this one is called the...
The potential of a silver electrode is measured relative to an Ag-AgCl electrode for the titration of 100.0 mL of 0.100 M Cl- with 0.100 M Ag+. What is the potential after 75.00 mL of titrant is added...
The potential of a silver electrode is measured relative to an Ag-AgCl electrode for the titration of 100.0 mL of 0.100 M Cl- with 0.100 M Ag+. What is the potential after 75.00 mL of titrant is added. Eo = 0.799 V for Ag+, E = 0.197 V for the Ag-AgCl electrode and Ksp = 1.8 × 10−10. A) 0.493 V B) 1.070 V C) 0.521 V D) 1.267 V E) 0.134 V Answer is E, can someone show me...
draw a diagram like figure 15-6 to convert the following potentials. The Ag|AgCl and calomel reference...
draw a diagram like figure 15-6 to convert the
following potentials. The Ag|AgCl and calomel reference elctrodes
are saturated with KCl
rcactions for the silver-silver chloride and exacly the vanue 15-1. (a) Write ts lomel val sse for the following cell. E for the calomel e (b) Predict the Predict t Indicator Electroe 15-6. A cell was calomel electrod attached to the electrode was a (a) Write a hal (b) Write the (c) Calculate Saturated silver-silver Saturated calomel chloride electrode...
2. A cell was prepared by dipping a AgCl/Ag wire and a saturated calomel electrode into...
2. A cell was prepared by dipping a AgCl/Ag wire and a saturated calomel electrode into 0.100 M Cl solution. The wire was attached to the positive terminal of a potentiometer and the calomel electrode was attached to the negative terminal. (a) Write a half-reaction for the AgCl/Ag electrode. (b) Write the Nernst equation for the Cu electrode. (c) Calculate the cell voltage.
0.598 V 1. (4.0 points, show your work) What is the mass of palladium (106.42 g/mole)...
0.598 V 1. (4.0 points, show your work) What is the mass of palladium (106.42 g/mole) in the 400.0 mL solution if the measured potential in is 0.598 Volt? Pd Electrode Pd SO Silver Silver Chloride electrode 400 ml NaBr (0.050 M) ((6.0 points) Knowing that Ksp of AsBr-5.0 x 10-13: A 30.0-ml solution of 0.050 M AgNO; was titrated with 0.0250 M NaBr in the cell: S.C.E. Il titration solution | Ag 2. (2.0 pointyFind the volume of NaBr...
- A40.0 mL. solution of 0.600 M Cu' in 1 M HNO was t titrated with...
- A40.0 mL. solution of 0.600 M Cu' in 1 M HNO was t titrated with 0.400 M Cef to give Cu and Ce The saturated calomel electrode was the reference e lectrode. (a) Write down the BALANCED titration reaction (b) Determine the equivalence volume. (c) Write the analyte half-reaction for the indicator electrode. (d) Write the titrant half-reaction for the indicator electrode (e) Write the analyte Nernst equation for the net cell reaction. (t) Write the titrant Nernst equation...
At 25 C, a titration of 15.00 mL of a 0.0440 M A^NO, solution with a...
At 25 C, a titration of 15.00 mL of a 0.0440 M A^NO, solution with a 0.0220 M Nal solution is conducted within the cell SCE | titration solution | Ag(s) For the cell as written, what is the potential after the addition of each volume of Nal solution? The reduction potential for the saturated calomel electrode is E = 0.241 V. The standard reduction potential for the reaction Ag+ + e _» Ag(s) is E = 0.79993 V. The...
Мар You are performing a titration of 25.0 mL of 0.0100 M Sn4 in 1 M HCI with 0.0500 M Ag* to give Sn2 anu 3+ Ags using...
Мар You are performing a titration of 25.0 mL of 0.0100 M Sn4 in 1 M HCI with 0.0500 M Ag* to give Sn2 anu 3+ Ags using a Pt indicator electrode and a saturated calomel electrode (SCE) as the reference electrode. A) Write the balanced titration reaction B) Complete the two half-reactions that occur at the indicator electrode (shown is their corresponding reduction potential) Sn E 0.139 V 3+ Ag® Eo 1.90 V C) Choose the two different expressions...
0. (15 points) An analytical chemist conducted the titration of 50.00 mL of 0.100 M Ag using 0.150 M CT solution. Silver wire is the indicator electrode and the saturated Ag-AgCl electrode is the reference electrode. E = 0.197 V for the saturated Ag-AgCl electrode, EºAg+/Ag= 0.1993 and Ksp = 1.8 x 10-8 for AgCI a) Calculate E at the volume of Cl' is 25.0 mL. Show all your work. b) Calculate E at the volume of Cl' is 50.0...
please answer the following question
2. Calculate E for the titration of 48.00 mL of 0.110 M Ag when 50.00 mL of 0.140 M Cl" is added. Silver wire is the indicator electrode and the saturated Ag-AgCl electrode is the reference electrode. E=0.197 V for the saturated Ag-AgCl electrode, E.= 0.7993 V and Ksp = 1.8 10- for AgCl.
i
answered 0.58 but I got it wrong.
can you help/solve?
Question:
A chemist measures the potential of an electrochemical cell
vs. the saturated calomel electrode to be +0.5V. Then, the chemist
switches the reference electrode to the silver-silver chloride
electrode.
What should the voltage read?
Use the following diagram to assist your thought
process:
Previously we discussed a calomel reference electrode. A second type of reference electrode is also very common in lab - this one is called the...
draw a diagram like figure 15-6 to convert the
following potentials. The Ag|AgCl and calomel reference elctrodes
are saturated with KCl
rcactions for the silver-silver chloride and exacly the vanue 15-1. (a) Write ts lomel val sse for the following cell. E for the calomel e (b) Predict the Predict t Indicator Electroe 15-6. A cell was calomel electrod attached to the electrode was a (a) Write a hal (b) Write the (c) Calculate Saturated silver-silver Saturated calomel chloride electrode...
2. A cell was prepared by dipping a AgCl/Ag wire and a saturated calomel electrode into 0.100 M Cl solution. The wire was attached to the positive terminal of a potentiometer and the calomel electrode was attached to the negative terminal. (a) Write a half-reaction for the AgCl/Ag electrode. (b) Write the Nernst equation for the Cu electrode. (c) Calculate the cell voltage.
0.598 V 1. (4.0 points, show your work) What is the mass of palladium (106.42 g/mole) in the 400.0 mL solution if the measured potential in is 0.598 Volt? Pd Electrode Pd SO Silver Silver Chloride electrode 400 ml NaBr (0.050 M) ((6.0 points) Knowing that Ksp of AsBr-5.0 x 10-13: A 30.0-ml solution of 0.050 M AgNO; was titrated with 0.0250 M NaBr in the cell: S.C.E. Il titration solution | Ag 2. (2.0 pointyFind the volume of NaBr...
- A40.0 mL. solution of 0.600 M Cu' in 1 M HNO was t titrated with 0.400 M Cef to give Cu and Ce The saturated calomel electrode was the reference e lectrode. (a) Write down the BALANCED titration reaction (b) Determine the equivalence volume. (c) Write the analyte half-reaction for the indicator electrode. (d) Write the titrant half-reaction for the indicator electrode (e) Write the analyte Nernst equation for the net cell reaction. (t) Write the titrant Nernst equation...
At 25 C, a titration of 15.00 mL of a 0.0440 M A^NO, solution with a 0.0220 M Nal solution is conducted within the cell SCE | titration solution | Ag(s) For the cell as written, what is the potential after the addition of each volume of Nal solution? The reduction potential for the saturated calomel electrode is E = 0.241 V. The standard reduction potential for the reaction Ag+ + e _» Ag(s) is E = 0.79993 V. The...
Мар You are performing a titration of 25.0 mL of 0.0100 M Sn4 in 1 M HCI with 0.0500 M Ag* to give Sn2 anu 3+ Ags using a Pt indicator electrode and a saturated calomel electrode (SCE) as the reference electrode. A) Write the balanced titration reaction B) Complete the two half-reactions that occur at the indicator electrode (shown is their corresponding reduction potential) Sn E 0.139 V 3+ Ag® Eo 1.90 V C) Choose the two different expressions...
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