Question

Flgure 23-44 Problem 39 40. Determine the unknown index of refraction in each of the situations in Figure 23- 45. Example 23-1 1.00 fc) Figure 23-45 Problem 40
whats the answer

Answer 1

Part (a)

n₁ = 1

$\theta$ ₁ = 20^o

n₂ = ?

$\theta$ ₂ = 14^o

By Snell's law,

n₁Sin $\theta$ ₁ = n₂Sin $\theta$ ₂

(1)Sin(20) = n₂Sin(14)

n₂ = 1.413

Part (b)

n₁ = 1

$\theta$ ₁ = 30^o

n₂ = ?

$\theta$ ₂ = 20^o

By Snell's law,

n₁Sin $\theta$ ₁ = n₂Sin $\theta$ ₂

(1)Sin(30) = n₂Sin(20)

n₂ = 1.462

Part (c)

n₁ = ?

$\theta$ ₁ = 18^o

n₂ = 1.5

$\theta$ ₂ = 10^o

By Snell's law,

n₁Sin $\theta$ ₁ = n₂Sin $\theta$ ₂

n₁Sin(18) = (1.5)Sin(10)

n₁ = 0.843

Part (d)

n₁ = ?

$\theta$ ₁ = 34.1^o

n₂ = 1.33

$\theta$ ₂ = 25^o

By Snell's law,

n₁Sin $\theta$ ₁ = n₂Sin $\theta$ ₂

n₁Sin(34,1) = (1.33)Sin(25)

n₁ = 1.002