int arr[] = {1,4, 1, 0); for (int i=0; i < 4; ++i) cout<<arr[i]*2; 0140 1014...
Consider the following function definition and variable declarations: void square(int &n){n= n*n;} int arr[] = {1, 2, 3}; int number = 4; Which of the following function calls are acceptable? (can have multiple answer) a.square(1); b.square(2); c.square(arr[number]); d.square(number); What is the output of the following code segment? int arr[] = {1, 4, 1, 0}; for (int i=0; i < 4; ++i) cout<<arr[i]*2; a.1014 b.1 4 1 0 (space in between each number) c.1410 d.0140 e.None of the above Given...
homework c++ find the error/correction void Showval (int n) for (int i = 0; i<10;-) cout <<n [i; )
what is the output of the following code segment? C++ g. int arr[3][4]; for (int i = 0; i < 3; i++) for (int j = 0; j < 4; j++) arr[i][j] =i*4 + j; for (int i = 0; i < 3; i++) for (int j = 0; j < 4; j++) cout << arr[i][j] << " "; h. int next(int & x) { x= x + 1; return (x + 1); int main() { int y = 10;...
#include <iostream> using namespace std; bool binarySearch(int arr[], int start, int end, int target){ //your code here } void fill(int arr[], int count){ for(int i = 0; i < count; i++){ cout << "Enter number: "; cin >> arr[i]; } } void display(int arr[], int count){ for(int i = 0; i < count; i++){ cout << arr[i] << endl; } } int main() { cout << "How many items: "; int count; cin >> count; int * arr = new...
5. What is the Big Oh method m2? public static void m2(int[] arr, int n) for (int í = 1; í <= n- 1; i++) pM2(arr [i], arr, 0, i - 1); // end m2 private static void pM2(int entry, int[l arr, int begin, int end) int i- end; for(; (i 〉= begin) && (entry 〈 arr [i]); i--) arr [1 + 1] = arr L1] arr[i + 1] - entry; return // end pM2
1) Fix the Function #include <iostream> void print Num() { std::cout << number; }; int main() { int number = 35; printNum (number); return 0; (Give two ways to fix this code. Indicate which is preferable and why.) #include <iostream> void double Number (int num) {num = num * 2;} int main() { int num = 35; double Number (num); std::cout << num; // Should print 70 return 0; (Changing the return type of doubleNumber is not a valid solution.)
Complete the mult() and printArr() functions #include <iostream> using namespace std; void init(int arr]05], int x)t //initialization loop for row 1 and 2 for(int i = 0; i < 2; i++){ arr i][j] x; void mult(int arr JSD //multiply the elements of row 2 by row 1, and store result in row3 void printArr int arr ][5]) // a loop to print out all the elements of the array int main) int arr[3105] 31 int x 32 34 // initialize...
QUESTION: //Sort the array arr[] for (int i = 0; i < arr.length - 1; i++) { //outer int index = i; for (int j = i + 1; j < arr.length; i++) if (arr[j] < arr[index]) index = j; int smallerNumber = arr[index]; arr[index] = arr[i]; arr[i] = smallerNumber; }//for i In the array= 16 13 15 14 19 24 9 3, the index of the smallest number at the outer iteration 4 = Answer
(a) Consider the following C++ function: 1 int g(int n) { 2 if (n == 0) return 0; 3 return (n-1 + g(n-1)); 4} (b) Consider the following C++ function: 1 bool Function (const vector <int >& a) { 2 for (int i = 0; i < a. size ()-1; i ++) { 3 for (int j = i +1; j < a. size (); j ++) { 4 if (a[i] == a[j]) return false; 5 6 } 7 return...
Implement merge sort and merge #include <iostream> using namespace std; void * merge(int arr[], int start1, int end1, int start2, int end2){ int * combined = new int[end2-start1 + 1]; } void mergeSort(int arr[], int start, int end){ //base case: down to 1 item, do nothing //recursive case: //MergeSort(left) //MergeSort(right) //Merge(left, right) int m = (end - start) / 2; if(start==end){ } else { mergeSort(arr, start, m); mergeSort(arr, m+1, end); merge(arr, start, m, m+1, end); } } void fill(int arr[],...