B=-0.01005，first
peak delta t=0.18s and Vavg=-0.111，second peak delta t=0.211s and
Vavg=0.118
Homework Answers
5. Given data,
B=-0.01005 T
first peak delta t=0.18s and Vavg=-0.111 volts
emf, v =NAB/change in time,
N = no of turns is a number always positve.
-0.111 = N A (-0.01005) / 0.18
A= area = 1.988 / N (positive value)
There fore change in area vector will be in positive direction.
8. second peak delta t=0.211s and Vavg=0.118
emf, v =NAB/change in time,
N = no of turns is a number always positve.
0.118 = N A (-0.01005) / 0.211
A= area = -2.4774 / N (negative value)
There fore change in area vector will be in negative direction.
Add Answer to:
B=-0.01005，first
peak delta t=0.18s and Vavg=-0.111，second peak delta t=0.211s and
Vavg=0.118
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