Question
please show me what hand written function to use and exactly how to use it. thanks!
By formula By Function 2.89 0.974632693 WN relation is the one between the res of year and The National Safety Council of the

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Answer #1

Given,

year 1 year 2 year 3
0.46 0.48 0.69
0.52 0.62 0.63
0.9 0.72 0.81
1.5 1.74 2.1
2.89 2.03 2.46
1.8 1.92 2
3.29 3.18 3.17
5.73 4.43 4

r1 : Correlation between year1: x and year2: y

\small r1=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{ \left [ n\Sigma x^{2} -(\Sigma x)^{2}\right ]\left [ n\Sigma y^{2}-(\Sigma y)^{2} \right ]}}

n : Number of observations:8

year 1:x year 2:y xy x2 y2
0.46 0.48 0.2208 0.2116 0.2304
0.52 0.62 0.3224 0.2704 0.3844
0.9 0.72 0.648 0.81 0.5184
1.5 1.74 2.61 2.25 3.0276
2.89 2.03 5.8667 8.3521 4.1209
1.8 1.92 3.456 3.24 3.6864
3.29 3.18 10.4622 10.8241 10.1124
5.73 4.43 25.3839 32.8329 19.6249
Total \small \Sigma x=17.09 \small \Sigma y=15.12 \small \Sigma xy=48.97 \small \Sigma x^{2}=58.7911 \small \Sigma y^{2}=41.7054

\small r1=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{ \left [ n\Sigma x^{2} -(\Sigma x)^{2}\right ]\left [ n\Sigma y^{2}-(\Sigma y)^{2} \right ]}}

\small \\=\frac{8\times48.97-17.09\times15.12}{\sqrt{ \left [8\times58.7911 -(17.09)^{2}\right ]\left [8\times41.7054-(15.12)^{2} \right ]}}\\\\\\=\frac{391.76-258.4008}{\sqrt{ \left [470.3288 -292.0681\right ]\left [333.6432-228.6144 \right ]}}

\small =\frac{133.3592}{\sqrt{ 18722.50740816 }}=0.97463269

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r2: Correlation between year2: x and year3: y

\small r2=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{ \left [ n\Sigma x^{2} -(\Sigma x)^{2}\right ]\left [ n\Sigma y^{2}-(\Sigma y)^{2} \right ]}}

year 2:x year 3:y xy x2 y2
0.48 0.69 0.3312 0.2304 0.4761
0.62 0.63 0.3906 0.3844 0.3969
0.72 0.81 0.5832 0.5184 0.6561
1.74 2.1 3.654 3.0276 4.41
2.03 2.46 4.9938 4.1209 6.0516
1.92 2 3.84 3.6864 4
3.18 3.17 10.0806 10.1124 10.0489
4.43 4 17.72 19.6249 16
Total \small \Sigma x=15.12 \small \Sigma y=15.86 \small \Sigma xy=41.5934 \small \Sigma x^{2}=41.7054 \small \Sigma y^{2}=42.0396

\small r2=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{ \left [ n\Sigma x^{2} -(\Sigma x)^{2}\right ]\left [ n\Sigma y^{2}-(\Sigma y)^{2} \right ]}}

\small =\frac{8\times41.5934-15.12\times15.86}{\sqrt{ \left [8\times41.7054 -(15.12)^{2}\right ]\left [8\times42.0396-(15.86)^{2} \right ]}} \\\\\\=\frac{332.7472-239.8032}{\sqrt{ \left [333.6432 -228.6144\right ]\left [336.3168-251.5396 \right ]}} \\\\\\=\frac{92.944}{\sqrt{ 8904.04758336 }} =0.98498048

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r3 : Correlation between year1: x and year3: y

\small r3=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{ \left [ n\Sigma x^{2} -(\Sigma x)^{2}\right ]\left [ n\Sigma y^{2}-(\Sigma y)^{2} \right ]}}

year 1:x year 3 xy x2 y2
0.46 0.69 0.3174 0.2116 0.4761
0.52 0.63 0.3276 0.2704 0.3969
0.9 0.81 0.729 0.81 0.6561
1.5 2.1 3.15 2.25 4.41
2.89 2.46 7.1094 8.3521 6.0516
1.8 2 3.6 3.24 4
3.29 3.17 10.4293 10.8241 10.0489
5.73 4 22.92 32.8329 16
Total \small \Sigma x=17.09 \small \Sigma y=15.86 \small \Sigma xy=48.5827 \small \Sigma x^{2}=58.7911 \small \Sigma y^{2}=42.0396

\small =\frac{8\times48.5827-17.09\times15.86}{\sqrt{ \left [8\times58.7911 -(17.09)^{2}\right ]\left [8\times42.0396-(15.86)^{2} \right ]}} \\\\\\=\frac{388.6616-271.0474}{\sqrt{ \left [470.3288 -292.0681\right ]\left [336.3168-251.5396 \right ]}} \\\\\\=\frac{117.6142}{\sqrt{ 15112.44301604 }} =0.95673667

---------------------------------------------

Using Excel function Correl

1586158112686_image.png

By formula By function
r1 Year 1 and Year 2 0.97463269 0.97463269
r2 Year 2 and Year 3 0.98498048 0.98498048
r3 Year 1 and Year 3 0.95673667 0.95673667

The highest correlation is between Year 2 and Year 3: which 0.98498048

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