Question
scheduling program in C, please help
1 Objectives This programming project is to simulate a few CPU scheduling policies discussed in the class. You will write a C
Examples proj2 input.1 FCFS proj2 input.1 RR 2 Description FCFS scheduling with the data file input.1 Simulate RR schedulin
7. Appendix: about input file and output information by CPU scheduling simulator for FCFS, RR, and SRTF more input. 1010 5 10
Avarage cpu usage 100.00 Avarage waiting time 16.17 Avarage response time 14.17 Avarage turnaround timet 21.00 proj2 input.1
pros2 input. SRF Sehiduling algorithm SRT Total 6 tasks are read from input.1. press enter to start... <system time 0> proce
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Answer #1

Code implemented in C programming

Note: Comments are written for code explanation

Filename: program.c

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <math.h>

//To implement first come first serve scheduling
void fcfs(int, int[], int[], int[]);  
//To implement round robin scheduling
void rr(int, int[], int[], int[], int);
//To implement shortest runtime first
void srtf(int, int[], int[], int[]);
//To calculate turn around time
void turn_around(int, int [], int []);
//To calculate the CPU usage
void cpu_usage(int, int[], int);
//For duplicating arrays
void copy_array(int, int[], int[]);

int main(int argc, char *argv[])
{
   //Size of the array
   int size = 0;
   //Time quantum of the scheduling
   int quantum;
   //Information read from the read file
   int pid[20], arrival_time[20], burst_time[20];
   //Variable for the read file
   FILE *file;
   //Sets the file to read
   file = fopen(argv[1], "r");
  
   if ((argc < 3) || (argc > 4))
   {
       printf("Usage: proj2 input_file FCFS|RR|SRJF [quantum]\n");
   }
   else
   {
       if (file)
       {
           while (!feof(file))
           {
               fscanf(file, "%d %d %d", &pid[size], &arrival_time[size], &burst_time[size]);
               size += 1;
           }
       }
  
       //No process in the queue, queue is empty
       if(size == 0)
       {
           goto empty_queue;
       }

       printf("Schdeuling Algorithm: ");
       //First-Come-First-Serve
       if (!strcmp(argv[2], "FCFS"))
       {
           printf("FCFS\n");
           fcfs(size, pid, burst_time, arrival_time);  
       }
       else if (!strcmp(argv[2], "RR"))
       {
           if (argc == 4)
           {
               printf("RR\n");
               quantum = atoi(argv[3]);
               rr(size, pid, burst_time, arrival_time, quantum);
           }
           else
           {
               printf("...\n Invalid Entry\n");
           }
       }
       else if (!strcmp(argv[2], "SRTF"))
       {
           printf("SRTF\n");
           srtf(size, pid, burst_time, arrival_time);
       }
       else
       {
           printf("USAGE: FCFS, RR, SRTF\n");
       }
   }
   /* end of run */
   return 0;

   empty_queue: printf("\nProcess queue is empty. End of run.\n");
}

//SRTF: To implement shortest run-time first
void srtf(int size, int pid[], int burst_time[], int arrival_time[])
{
   int i, j, n, k, time, result;
   int temp_burst[size], waiting[size], response_time[size];
   int turnaround_time[size], wait_time[size];
   float float_result;
   bool done, processed[size];
   //Duplicates burst_time array
   copy_array(size, burst_time, temp_burst);
  
   printf("Total of %d tasks are read. Press 'enter' to start...", size);
   getchar();
   printf("==================================================================\n");
  
   //Initializes all processed to false
   for (i = 0; i < size; ++i)
   {
       processed[i] = false;
   }
   //Initializes the response time
   for (i = 0; i < size; ++i)
   {
       response_time[i] = -1;
   }
   //Initializes the wait time
   for (i = 0; i < size; ++i)
   {
       wait_time[i] = 0;
   }
  
   //Shortest Runtime First
   done = false;
   time = 0;
   while (!done)
   {
       n = 1000000;
       k = -1;
       for (i = 0; i < size; ++i)
       {
           if ((temp_burst[i] != 0) && (arrival_time[i] <= time))
           {
               if (temp_burst[i] < n)
               {
                   n = temp_burst[i];
                   k = i;
               }
           }
           else if ((temp_burst[i] == 0) && (processed[i] != true))
           {
               printf("<System Time\t%d> Process: %d\t...is finished;\n", time, pid[i]);
               processed[i] = true;
               turnaround_time[i] = time - arrival_time[i];
           }
       }
       if (k != -1)
       {
           printf("<System Time\t%d> Process: %d\t...is running;\n", time, pid[k]);
           temp_burst[k] -= 1;
           if (response_time[k] == -1)
           {
               response_time[k] = time - arrival_time[k];
           }
       }
       for (i = 0; i < size; ++i)
       {
           if ((temp_burst[i] != 0) && (arrival_time[i] <= time))
           {
               if (k != i)
               {
                   wait_time[i] += 1;
               }
           }
       }
       done = true;
       for (i = 0; i < size; ++i)
       {
           if ( processed[i] != true)
           {
               done = false;
               time += 1;
               break;
           }
       }
   }
   printf("<System Time\t%d> ...All processes finished;\n", time);
   printf("==================================================================\n");
  
   //CPU Usage
   cpu_usage(size, burst_time, time);
  
   //Average Wait Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += wait_time[i];
   }
   float_result = 1.0 * ((float)result/(float)size);
   printf("Average Wait Time\t: %.2f\n", float_result);
  
   //Average Response Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += response_time[i];
   }
   float_result = 1.0 * ((float)result/(float)size);
   printf("Average Response Time\t: %.2f\n", float_result);
  
   //Average Turn Around Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += turnaround_time[i];
   }
   float_result = 1.0 * ((float)result/(float)size);
   printf("Average Turn Around Time: %.2f\n", float_result);
}

//RR: To implement round robin scheduling
void rr(int size, int pid[], int burst_time[], int arrival_time[], int quantum)
{
   int i, j, n, remain, count, front, rear, time, result;
   int ready_queue[size], temp_burst[size], waiting[size], response_time[size];
   int turnaround[size], waittime[size];
   int flag = 0;
   float float_result;
   bool done, processed[size], waiting_queue[size];
   //Copies the real array into duplicate for modification
   copy_array(size, burst_time, temp_burst);
  
   printf("Total of %d tasks are read. Press 'enter' to start...", size);
   getchar();
   printf("==================================================================\n");
  
   //Determines if the index has been processed
   for (i = 0; i < size; ++i)
   {
       processed[i] = false;
   }
   for (i = 0; i < size; ++i)
   {
       response_time[i] = -1;
   }
   //Initializes the ready queue
   for (i = 0; i < size; ++i)
   {
       ready_queue[i] = -1;
   }
   //Initializes the waiting queue to false
   for (i = 0; i < size; ++i)
   {
       waiting_queue[i] = false;
   }
   //Initializes something
   for (i = 0; i < size; ++i)
   {
       waittime[i] = 0;
   }
  
   //Round Robin
   done = false;
   n = 0;
   time = 0;
   front = 0;
   rear = -1;
   while (!done)
   {
       check_queue: for (i = 0; i < size; ++i)
       {
           if ((arrival_time[i] <= time) && (temp_burst != 0) && (processed[i] != true))
           {
               waiting_queue[i] = false;
               for (j = 0; j < size; ++j)
               {
                   if (ready_queue[j] == i)
                   {
                       waiting_queue[i] = false;
                       break;
                   }
                   else
                   {
                       waiting_queue[i] = true;
                   }
               }
           }
           if (waiting_queue[i] == true)
           {
               rear = (rear + 1) % size;
               ready_queue[rear] = i;
           }
       }
       if (temp_burst[ready_queue[front]] == 0)
       {
           printf("<System Time\t%d> Process: %d\t...is finished;\n", time, pid[ready_queue[front]]);
           processed[ready_queue[front]] = true;
           turnaround[ready_queue[front]] = time - arrival_time[ready_queue[front]];
       }
       if ((n >= quantum) || (processed[ready_queue[front]] == true))
       {
           ready_queue[front] = -1;
           front = (front + 1) % size;
           if (n == quantum)
           {
               n = 0;
               goto check_queue;
           }
           n = 0;
       }
       if (ready_queue[front] != -1)
       {
           n += 1;
           temp_burst[ready_queue[front]] -= 1;
           if (response_time[ready_queue[front]] == -1)
           {
               response_time[ready_queue[front]] = time - arrival_time[ready_queue[front]];
           }
       }
       if (ready_queue[front] != -1)
       {
           printf("<System Time\t%d> Process: %d\t...is running;\n", time, pid[ready_queue[front]]);
       }
       done = true;
       for (i = 0; i < size; ++i)
       {
           if ((temp_burst[i] != 0) && (arrival_time[i] <= time))
           {
               if (ready_queue[front] != i)
               {
                   waittime[i] += 1;
               }
           }
       }
       for (i = 0; i < size; ++i)
       {
           if (processed[i] != true)
           {
               done = false;
               time += 1;
               break;
           }
       }
   }
   printf("<System Time\t%d> ...All processes finished;\n", time);
   printf("==================================================================\n");
  
   //Resets processed to false
   for (i = 0; i < size; ++i)
   {
       processed[i] = false;
   }
  
   //CPU Usage
   cpu_usage(size, burst_time, time);
  
   //Resets the temporary array
   copy_array(size, burst_time, temp_burst);
  
   //Average Wait Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += waittime[i];
   }
   float_result = 1.0 * ((float)result/(float)size);
   printf("Average Waiting Time\t: %.2f\n", float_result);
  
   //Average Response Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += response_time[i];
   }
   float_result = ((float)result/(float)size);
   printf("Average Response Time\t: %.2f\n", float_result);
  
   //Average Turn Around Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += turnaround[i];
   }
   float_result = 1.0 * ((float)result/(float)size);
   printf("Average Turn Around Time: %.2f\n", float_result);
}

//FCFS : To implement first come first serve scheduling
void fcfs(int size, int pid[], int burst_time[], int arrival_time[])
{
   int i, j, k, n, time, result;
   int temp_burst[size], first_response[size];
   int wait_time[size], turnaround_time[size];
   float float_result;
   bool done, processed[size];
   //Copies the real arrays into duplicates for modification
   copy_array(size, burst_time, temp_burst);
  
   printf("Total of %d tasks are read. Press 'enter' to start...", size);
   getchar();
   printf("==================================================================\n");
  
   //Determines if the index has been processed
   for (i = 0; i < size; ++i)
   {
       processed[i] = false;
   }
   //Initializes all of the first responses to -1
   for (i = 0; i < size; ++i)
   {
       first_response[i] = -1;
   }
   //Initializes you get the idea
   for (i = 0; i < size; ++i)
   {
       wait_time[i] = 0;
   }
  
   //First Come First Serve
   done = false;
   time = 0;
   while (!done)
   {
       n = 1000000;
       k = -1;
       for (i = 0; i < size; ++i)
       {
           if ((temp_burst[i]) != 0 && (arrival_time[i] <= time))
           {
               if ((arrival_time[i] < n))
               {
                   n = arrival_time[i];
                   k = i;
               }
           }
           else if ((temp_burst[i] == 0) && (processed[i] != true))
           {
               printf("<System Time\t%d> Process: %d\t...is finished;\n", time, pid[i]);
               processed[i] = true;
               turnaround_time[i] = time - arrival_time[i];
           }
       }
       if (k != -1)
       {
           printf("<System Time\t%d> Process: %d\t...is running;\n", time, pid[k]);
           temp_burst[k] -= 1;
           if (first_response[k] == -1)
           {
               first_response[k] = time - arrival_time[k];
           }
       }
       for (i = 0; i < size; ++i)
       {
           if ((temp_burst[i] != 0) && (arrival_time[i] <= time))
           {
               if (k != i)
               {
                   wait_time[i] += 1;
               }
           }
       }
       done = true;
       for (i = 0; i < size; ++i)
       {
           if (processed[i] != true)
           {
               done = false;
               time += 1;
               break;
           }
       }
   }
   printf("<System Time\t%d> ...All processes finished;\n", time);
   printf("==================================================================\n");
  
   //Determines if the index has been processed
   for (i = 0; i < size; ++i)
   {
       processed[i] = false;
   }
  
   //CPU Utilization
   cpu_usage(size, burst_time, time);
  
   //Average Waiting Time
   result = 0;
   for (i = 0; i < size; ++i)  
   {
       result += wait_time[i];
   }
   float_result = ((float)result/(float)size);
   printf("Average Waiting Time\t: %.2f\n", float_result);
  
   //Average Response Time
   result = 0;
   for (i = 0; i < size; ++i)
   {
       result += first_response[i];
   }
   float_result = ((float)result/(float)size);
   printf("Average Response Time\t: %.2f\n", float_result);

   //Turnaround Time
   turn_around(size, burst_time, wait_time);
}

/* turn_around : to calculate turn around time for each process */
void turn_around(int size, int burst_time[], int waiting[])
{
   int i;
   int turn_around_time[size];
   int result = 0;
   float float_result = 0.0;
  
   for(i = 0; i < size; ++i)
   {
       //Turn around time = burst time + waiting time
       turn_around_time[i] = burst_time[i] + waiting[i];
       result += turn_around_time[i];
   }
   float_result = ((float)result/(float)size);
   printf("Average Turn Around Time: %.2f\n", float_result);
}

void cpu_usage(int size, int burst_time[], int time)
{
   float float_result = 0.0;
   int result = 0;
   int i;
   for (i = 0; i < size; ++i)
   {
       result += burst_time[i];
   }
   float_result = 100.0 * ((float)result/(float)time);
   printf("Average CPU Usage\t: %%%.2f\n", float_result);
}

//Copies the content of one array into the other
void copy_array(int size, int A[], int B[])
{
   int i;
   for (i = 0; i < size; ++i)
   {
       B[i] = A[i];
   }
}

1 2 3 4 #include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <math.h> 6 // To implement first come first serv41 42 fscanf(file, %d %d %d, &pid[size], &arrival_time[size], &burst_time[size]); size += 1; 43 44 45 46 27 //No process in/* end of run */ return 0; empty_queue: printf(\nProcess queue is empty. End of run.\n); 88 89 90 //SRTF: To implement shor121 122 done = false; time = 0; while (!done) 123 124 125 126 127 128 129 130 131 n = 1000000; k = -1; for (i = 0; i < size;161 162 163 164 done = true; for (i = 0; i < size; ++i) 165 { if ( processed[i] != true) { 166 167 168 169 170 171 172 173 do202 NNNNNNNNN. 201 result += turnaround_time[i]; 203 204 float_result = 1.0 * ((float)result/(float)size); 205 printf(Averag241 waiting_queue[i] = false; 242 //Initializes something for (i = 0; i < size; ++i) waittime[i] = 0; 243 244 245 246 247 248281 if (temp_burst[ready_queue[front]] == 0) 282 283 284 printf(<System Time\t%d> Process: %d\t...is finished; \n, time, pi321 322 for (i = 0; i < size; ++i) if (processed[i] != true) 323 324 325 326 327 328 329 330 331 332 done = false; time += 1;361 362 363 float_result = ((float)result/(float)size); printf(Average Response Time\t: %.2f\n, float_result); 364 365 //Avfor (i = 0; i < size; ++i) 401 402 403 404 405 406 wait_time[i] = 0; 407 //First Come First Serve done = false; time = 0; whiif ((temp_burst[i] != 0) && (arrival_time[i] <= time)) if (k != i) wait_time[i] += 1; 441 442 443 444 445 446 447 448 449 450499 481 //Average Response Time 482 result = 0; 483 for (i = 0; i < size; ++i) 484 485 result += first response[i]; 486 487 ffloat_result = 100.0 * ((float)result/(float)time); printf(Average CPU Usage\t: %%%.2f\n, float_result); } 521 522 523 524

Working Code Output:

Schdeuling Algorithm: FCFS
Total of 6 tasks are read. Press 'enter' to start...
==================================================================
<System Time 0> Process: 1 ...is running;
<System Time 1> Process: 1 ...is running; <System Time 2> Process: 1 ...is running;
<System Time 3> Process: 1 ...is running;
<System Time 4> Process: 1 ...is running;
<System Time 5> Process: 1 ...is running;
<System Time 6> Process: 1 ...is running;
<System Time 7> Process: 1 ...is running;
<System Time 8> Process: 1 ...is running;
<System Time 9> Process: 1 ...is running;
<System Time 10> Process: 1 ...is finished;
<System Time 10> Process: 2 ...is running;
<System Time 11> Process: 2 ...is running;
<System Time 12> Process: 2 ...is running;
<System Time 13> Process: 2 ...is running;
<System Time 14> Process: 2 ...is running;
<System Time 15> Process: 2 ...is running;
<System Time 16> Process: 2 ...is running;
<System Time 17> Process: 2 ...is running;
<System Time 18> Process: 2 ...is running;
<System Time 19> Process: 2 ...is finished;
<System Time 19> Process: 3 ...is running;
<System Time 20> Process: 3 ...is running;
<System Time 21> Process: 3 ...is running;
<System Time 22> Process: 3 ...is running;
<System Time 23> Process: 3 ...is running;
<System Time 24> Process: 3 ...is finished;
<System Time 24> Process: 4 ...is running;
<System Time 25> Process: 4 ...is running;
<System Time 26> Process: 4 ...is running;
<System Time 27> Process: 4 ...is running;
<System Time 28> Process: 4 ...is finished;
<System Time 28> Process: 5 ...is running;
<System Time 29> Process: 5 ...is running;
<System Time 30> Process: 5 ...is running;
<System Time 31> Process: 5 ...is running;
<System Time 32> Process: 5 ...is running;
<System Time 33> Process: 5 ...is running;
<System Time 34> Process: 5 ...is finished;
<System Time 34> Process: 6 ...is running;
<System Time 35> Process: 6 ...is running;
<System Time 36> Process: 6 ...is running;
<System Time 37> Process: 6 ...is running;
<System Time 38> Process: 6 ...is running;
<System Time 39> Process: 6 ...is running;
<System Time 40> Process: 6 ...is running;
<System Time 41> Process: 6 ...is finished;
<System Time 41> ...All processes finished;
==================================================================
Average CPU Usage : %100.00
Average Waiting Time : 14.17
Average Response Time : 14.17
Average Turn Around Time: 21.00

Working Code Output Screenshot:

-->output input.1 FCFS Schdeuling Algorithm: FCFS Total of 6 tasks are read. Press enter to start... ======================<System Time 28> Process: 4 ...is finished; <System Time 28> Process: 5 ...is running; <System Time 29> Process: 5 ...is runn

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    1 - [30 pts] Scheduling Algorithms Comparison Assume that we have 5 independent and aperiodic tasks (T1, ... , Ts) and they arrive to the system at times indicated below. Each task will run for the amount of execution time listed and is assigned a priority ranging from 0 (highest) to 10 (lowest), i.e. lower value means higher priority. There are no other tasks scheduled to arrive to the system until T1, ... , Ts complete. Task Arrival Time Execution...

  • QUESTION 3 Consider the following set of processes: Priority Process Arrival Time A 0 B 1...

    QUESTION 3 Consider the following set of processes: Priority Process Arrival Time A 0 B 1 C 6 * Lower number means higher priority Burst Time (ms) 5 3 4 Draw in a paper sheet 4 Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, Non-Preemptive SJF, Shortest-Remaining-Time-First (SRTF), Non-Preemptive Priority (NPP), and RR (quantum time = 2) scheduling algorithms, then fill the following tabic accordingly. (Note: If a new process arrives at the...

  • Please answer the following question in C++ language Consider the following set of processes, with the...

    Please answer the following question in C++ language Consider the following set of processes, with the length of the CPU burst time given in milliseconds: Process            Burst Time      Priority P1. 7 5 P2 2 4 P3 11 3 P4 9 1 P5 5 3 The processes are assumed to have arrived in the order P1,P2, P3, P4, P5, all at time 0. a. Draw four Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, SJF, nonpreemptive...

  • Implement the following 3 CPU scheduling algorithms Simulate and evaluate each with the set of eight...

    Implement the following 3 CPU scheduling algorithms Simulate and evaluate each with the set of eight processes below. Use any programming language. The program listing should be submitted with the report. FCFS (First Come First Serve) non-preemptive (partial results provided) SJF non-preemptive MLFQ Multilevel Feedback Queue (absolute priority in higher queues)             Queue 1 uses RR scheduling with Tq = 5             Queue 2 uses RR scheduling with Tq = 10             Queue 3 uses FCFS All processes enter first...

  • Cpu scheduling

    Consider the following set of processes, with the length of the CPU burst times given in milliseconds:a. Draw four Gantt charts illustrating the execution of the processes using FCFS, Preemptive SJF, a non-preemptive priority, and a RR (quantum=2) scheduling. (30 pts)Note: for the RR consider that the arriving time is 0 for all processesb. What is the average waiting time of each process for of the above scheduling algorithms? (10 pts)P1 8 2 0 P2 5 36P3 1 1 8...

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    Question 4 [Points 4] Consider a system running 2 (two)CPU-bound tasks (C1-C2) and 1(one) I/O-bound tasks(I1). I/O bound task issues an I/O operation once every 1millisecond ofCPU. Each I/O operation takes 10milliseconds. Assume that there is only one I/O device (so multiple I/O requests may have to queue). Assume that the context switch takes 1 millisecond. Assume that each CPU-bound requires 20 milliseconds of CPU to complete and each I/O-bound task requires 2millisecondof CPU time. Show through a Ganttt chart...

  • Description In this homework, you are asked to implement a multithreaded program that will allow ...

    Description In this homework, you are asked to implement a multithreaded program that will allow us to measure the performance (i.e, CPU utilization, Throughput, Turnaround time, and Waiting time in Ready Queue) of the four basic CPU scheduling algorithms (namely, FIFO, SJE PR, and RR). Your program will be emulating/simulating the processes whose priority, sequence of CPU burst time(ms) and I'O burst time(ms) will be given in an input file. Assume that all scheduling algorithms except RR will be non-preemptive,...

  • QUESTION 1 Consider the following set of processes, with the length of the CPU burst time...

    QUESTION 1 Consider the following set of processes, with the length of the CPU burst time given in milliseconds: Process            Burst Time      Priority P1                    7                      5 P2                    2                      4 P3                    11                    3 P4                    9                      1 P5                    5                      3 The processes are assumed to have arrived in the order P1,P2, P3, P4, P5, all at time 0. a. Draw four Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, SJF, nonpreemptive priority (a smaller priority number implies a higher priority), and RR (quantum = 2). b. What...

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