The formula for power required in this case is given by:
Power = width x speed x draft per unit width.
In the above question, width = 28 feet, speed = 5 mph and draft per unit width = 300 lbs/feet.
Therefore, Power = 28*5**300 = 42000 lbs.mph
Conversion factor from horsepower to lbs.mph is 374.85.
Therefore the minimum power required for this tractor is 112 hp.
4.) A John Deere tractor is pulling a 28-foot tandem disk at a speed of 5...