Question

A cube sits in an electric field by E (2i+3j-2 k). One corner of a cube is at the origin with the opposite corner located at (1, 1. 1) m. What is the net (lux through the cube in c. 0 e. None of these
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Answer #1

field is constant.

so two opposite faces will have flux through them of same magnitude but of oppoiste sign.

thus sume of fluxes through all 6 faces will be zero.

flux = (flux1 - flux1) + (flux2 - flux2) + (flux3 - flux3)

flux = 0

Ans: (c) 0

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