Question

KKTCELL TCELL 8.4K/s 36...11 26...65% + 5:15 PM EE227_S20_F01.pdf 2. 100 UA (40 marks) Consider the circuit with a silicon npn transistor shown on the right. Determine the a) parameters: Vae: VCE la and I assuming that ß = 100. b) mode of operation. Justify your answer. Show All Your Work SV END OF EXAM 1 of 2 о V

Answer 1

(a)

VBE

Given transistor is Si npn Transistor VBE=0.7

VCE

VCE =VC -VE

=5 Volts

IB

IB =100 micro Amp

IC

$I_{C}=\beta I_{B}$

=100*100*10-6

=0.01 Amp

=10 milli Amp

(b) As it is npn transistor

JBE is forward Bias and JCB  is Reverse Bias then it is acting as Amplifier.
В Р for silicon non transistor Vee = 0.7V JB = 100uA Ic VCE=5v " by de fault Іс - 10 +1. and. T. - puѕt авс les pie It VBE figure ! CScanned with CamScanner

Р n n +59 P Z col Z IBE B JCB Luc VIE IB: 100 MA VBE ulilit 니 figure a and VcB As Emitter-base is forward bias Reverse bias Collector-base is then transistor act as act as Amplifier CScanned with CamScanner

Here in the fig JBE is FB as current is flowing from B so 'P' it is connected to +ve terminal and E i.e N is connected to ground.So,JBE is FB.

JCB is RB as 'P' it is connected to +ve terminal and C i.e N is connected to +5V.So,JCB is RB.

Thus we can say that above transistor is operating in amplifier mode.