Question

A boy throws a ball off the top of a building with a speed of 5.0 m/s at an angle of 40.0° to the horizontal. If the ball strikes the ground 4.00 s later, how tall is the building? 6.
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Answer #1

By Newton's Law we have,

s = v0sin(theta)*t + 1/2gt^2

s = 5*sin(40)(4) + 0.5(9.8)(4)^2
= 91.24 m

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