A crate of mass 40 kg is pushed up a ramp by a person as shown...
A crate of mass 40 kg is pushed up a ramp by a person as shown in the figure below. The person pushes the crate a distance of 30 m as measured along the ramp. Assume the crate moves at constant velocity. Assume the coefficient of kinetic friction between the crate and the ramp is μK = 0.30. Find the work done by gravity on the crate.
Homework Answers
the gravitiational force acting downward is given by mg*sin(theta)
i guess your given angle is 30 degrees.
so , the work done by gravity = mgsin(theta) * 30 * cos ( 180 )
= -5880N
also there is work done by friction ,
give as[ mu* mg *cos(theta) ]* 30* cos(180)
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