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according to a recent reporting on a standardized test, the average EWR (English, Reading, Writing) score for students in a particular state was 518. Assume the scores are Normally distributed with a standard deviation of 102. What is the percentage that scored 500 or less?OA. B. 500 5000 Density Density 212 518 824 212 518 824 500 500 Density a Density 212 518 824 212 518 824

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Answer #1

D. 500 Density 212 518 824

µ =    518      
σ =    102      
          
P( X ≤    500   ) = P( (X-µ)/σ ≤ (500-518) /102)  
=P(Z ≤   -0.18   ) =   0.43

=43%

.......................

Please let me know in case of any doubt.

Thanks in advance!


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